1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
grandymaker [24]
3 years ago
11

The basketball team scored 89 points in just two- and and three baskets. The number of two points baskets was 27 more than the n

umber of three point baskets. How many two point and three pointers did the team make?
Mathematics
1 answer:
kvv77 [185]3 years ago
3 0

Answer:

The team made 27 two pointers and 7 three pointers.

Step-by-step explanation:

We can solve this question by a system of equations.

I am going to say that:

x is the number of two point baskets.

y is the number of three point baskets.

The team scored 89 points

This means that 2x + 3y = 89

The number of two points baskets was 27 more than the number of three point baskets.

This means that x = 27 + y

So

2x + 3y = 89

2(27 + y) + 3y = 89

54 + 2y + 3y = 89

5y = 35

y = \frac{35}{5}

y = 7

x = 27 + y = 27 + 7 = 34

The team made 27 two pointers and 7 three pointers.

You might be interested in
What is the solution to the equation<br><br>1+1
sveta [45]

Answer:

2

Step-by-step explanation:

but I would personally say FISH

8 0
3 years ago
POINTS Please HurryHassan helps his dad with newspaper deliveries. He gets $5 every morning and 10 cents for every paper deliver
dedylja [7]

Answer:

(20.60-5)/0.10=156 Papers

Step-by-step explanation:

4 0
2 years ago
Read 2 more answers
PLEASE HELP WILL GIVE A BRAINLIEST!!
Tanya [424]
The answer is a. number of boys < 89.
7 0
3 years ago
Read 2 more answers
The author drilled a hole in a die and filled it with a lead​ weight, then proceeded to roll it 199 times. Here are the observed
Anton [14]

Answer with explanation:

An Unbiased Dice is Rolled 199 times.

Frequency of outcomes 1,2,3,4,5,6 are=28​, 29​, 47​, 40​, 22​, 33.

Probability of an Event

      =\frac{\text{Total favorable Outcome}}{\text{Total Possible Outcome}}\\\\P(1)=\frac{28}{199}\\\\P(2)=\frac{29}{199}\\\\P(3)=\frac{47}{199}\\\\P(4)=\frac{40}{199}\\\\P(5)=\frac{22}{199}\\\\P(6)=\frac{33}{199}\\\\\text{Dice is fair}\\\\P(1,2,3,4,5,6}=\frac{33}{199}

→→→To check whether the result are significant or not , we will calculate standard error(e) and then z value

1.

(e_{1})^2=(P_{1})^2+(P'_{1})^2\\\\(e_{1})^2=[\frac{28}{199}]^2+[\frac{33}{199}]^2\\\\(e_{1})^2=\frac{1873}{39601}\\\\(e_{1})^2=0.0472967\\\\e_{1}=0.217478\\\\z_{1}=\frac{P'_{1}-P_{1}}{e_{1}}\\\\z_{1}=\frac{\frac{33}{199}-\frac{28}{199}}{0.217478}\\\\z_{1}=\frac{5}{43.27}\\\\z_{1}=0.12

→→If the value of z is between 2 and 3 , then the result will be significant at 5% level of Significance.Here value of z is very less, so the result is not significant.

2.

(e_{2})^2=(P_{2})^2+(P'_{2})^2\\\\(e_{2})^2=[\frac{29}{199}]^2+[\frac{33}{199}]^2\\\\(e_{2})^2=\frac{1930}{39601}\\\\(e_{2})^2=0.04873\\\\e_{2}=0.2207\\\\z_{2}=\frac{P'_{2}-P_{2}}{e_{2}}\\\\z_{2}=\frac{\frac{33}{199}-\frac{29}{199}}{0.2207}\\\\z_{2}=\frac{4}{43.9193}\\\\z_{2}=0.0911

Result is not significant.

3.

(e_{3})^2=(P_{3})^2+(P'_{3})^2\\\\(e_{3})^2=[\frac{47}{199}]^2+[\frac{33}{199}]^2\\\\(e_{3})^2=\frac{3298}{39601}\\\\(e_{3})^2=0.08328\\\\e_{3}=0.2885\\\\z_{3}=\frac{P_{3}-P'_{3}}{e_{3}}\\\\z_{3}=\frac{\frac{47}{199}-\frac{33}{199}}{0.2885}\\\\z_{3}=\frac{14}{57.4279}\\\\z_{3}=0.24378

Result is not significant.

4.

(e_{4})^2=(P_{4})^2+(P'_{4})^2\\\\(e_{4})^2=[\frac{40}{199}]^2+[\frac{33}{199}]^2\\\\(e_{4})^2=\frac{3298}{39601}\\\\(e_{4})^2=0.06790\\\\e_{4}=0.2605\\\\z_{4}=\frac{P_{4}-P'_{4}}{e_{4}}\\\\z_{4}=\frac{\frac{40}{199}-\frac{33}{199}}{0.2605}\\\\z_{4}=\frac{7}{51.8555}\\\\z_{4}=0.1349

Result is not significant.

5.

(e_{5})^2=(P_{5})^2+(P'_{5})^2\\\\(e_{5})^2=[\frac{22}{199}]^2+[\frac{33}{199}]^2\\\\(e_{5})^2=\frac{1573}{39601}\\\\(e_{5})^2=0.03972\\\\e_{5}=0.1993\\\\z_{5}=\frac{P'_{5}-P_{5}}{e_{5}}\\\\z_{5}=\frac{\frac{33}{199}-\frac{22}{199}}{0.1993}\\\\z_{5}=\frac{11}{39.6610}\\\\z_{5}=0.2773

Result is not significant.

6.

(e_{6})^2=(P_{6})^2+(P'_{6})^2\\\\(e_{6})^2=[\frac{33}{199}]^2+[\frac{33}{199}]^2\\\\(e_{6})^2=\frac{2178}{39601}\\\\(e_{6})^2=0.05499\\\\e_{6}=0.2345\\\\z_{6}=\frac{P'_{6}-P_{6}}{e_{6}}\\\\z_{6}=\frac{\frac{33}{199}-\frac{33}{199}}{0.2345}\\\\z_{6}=\frac{0}{46.6655}\\\\z_{6}=0

Result is not significant.

⇒If you will calculate the mean of all six z values, you will obtain that, z value is less than 2.So, we can say that ,outcomes are not equally likely at a 0.05 significance level.

⇒⇒Yes , as Probability of most of the numbers that is, 1,2,3,4,5,6 are different, for a loaded die , it should be equal to approximately equal to 33 for each of the numbers from 1 to 6.So, we can say with certainty that loaded die behaves differently than a fair​ die.

   

8 0
2 years ago
What is the volume of this prism? 10m, 5m, 3.2m
Assoli18 [71]
By using the volume formula multiple the length, width, and height and you get 53 as your volume.
3 0
2 years ago
Other questions:
  • What is the following product? 3√16x^7 3√12x^9 <br><br> Please help, Thank you!
    5·2 answers
  • ANSWER PLEASE I WILL MARK AS BRAINLIEST
    15·1 answer
  • an automobile 16 feet long overtakes a truck that is 28 feet long and is traveling 30 mph. At what rate must the automobile trav
    13·1 answer
  • Which juice container is larger 2 L or 1 gallon
    14·1 answer
  • A sport jacket that sells for $165 has a markup of $85. Find the wholesale price.
    8·2 answers
  • Solve for c: b/c =a<br>​
    8·1 answer
  • Y varies directly with x, and y = 15 when x = 3. What is the value of x when y = 4?
    15·2 answers
  • 5162x40 please sir i don´t feel like doing this sh/ it
    9·1 answer
  • 29 POINTS PLUS BRAINLIEST PLEASE ANSWER THESE MATH QUESTIONS.ALL TROLL ANSWERS WILL BE REPORTED MUST BE DONE IN 20min OR.LESS.
    8·2 answers
  • 12. What fraction is equivalent to 0.5?
    6·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!