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svetlana [45]
2 years ago
12

Dennis has three identical ​cylinders​ filled with water. How many ​cones should he be able to fill with the water if the cones

have the same radius and the same height as the cylinders?
Mathematics
2 answers:
docker41 [41]2 years ago
5 0

Answer:

9 cones

Step-by-step explanation:

The formula to find a volume of a cylinder is:

V1 = pi*r^2*h

Where r is the base radius and h is the height

The formula to find a volume of a cone is:

V2 = (1/3)*pi*r^2*h

So, if they have the same base radius and same height, we have that:

V1/V2 = 1/(1/3) = 3

The volume of the cylinder is 3 times bigger than the volume of the cone, so each cylinder of water can fill 3 cones.

Is Dennis has 3 cylinders, he is able to fill 3*3 = 9 cones with water.

Brut [27]2 years ago
3 0

Answer:

3 cylinder will fill 9 cones with water

Step-by-step explanation:

This problem bothers on mensuration of slides, cone and cylinder

We know that the

Volume of a cylinder = πr²h

Volume of a cone = 1/3(πr²h)

Given that both cylinder and cone has same height and radius

From the given expression we can deduce that the cone is 3 times smaller than the cylinder in volume

So if 1 cylinder will fill 3 cones

Then 3 cylinders will fill x cones

By cross multiplication we have

x= 3*3cones

x= 9 cones

Hence 3 cylinder will fill 9 cones with water

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Answer:

0.7 - 2.58 \sqrt{\frac{0.7(1-0.7)}{500}}=0.647

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And the 99% confidence interval would be given (0.647;0.753).

So the correct answer would be:

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Step-by-step explanation:

Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

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Solution to the problem

The estimated population proportion for this case is:

\hat p = \frac{350}{500}=0.7

The confidence interval would be given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 99% confidence interval the value of \alpha=1-0.99=0.01 and \alpha/2=0.005, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=2.58

And replacing into the confidence interval formula we got:

0.7 - 2.58 \sqrt{\frac{0.7(1-0.7)}{500}}=0.647

0.7 + 2.58 \sqrt{\frac{0.7(1-0.7)}{500}}=0.753

And the 99% confidence interval would be given (0.647;0.753).

So the correct answer would be:

a. 0.647 and 0.753

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