Answer:
Step-by-step explanation:
Roots of the equation are -4 and -3.
Quadratic equation can be written as
The general form of the given equation is 2x+y-6 = 0.
<u>Step-by-step explanation</u>:
- The given linear equation is 2x+y=6.
- The general form of the equation is AX+BY+C=0.
where,
- A is the co-efficient of x.
- B is the co-efficient of y.
- C is the constant term.
<u>From the given equation 2x+y=6, it can be determined that</u> :
The co-efficient of x is 2. It is in the form AX = 2x. Thus, no change is needed.
The co-efficient of y is 2. It is in the form BY = 1y. Thus, no change is needed.
The constant term 6 should be replaced to the left side of the equation, since the right side of the equation must be 0 always.
While moving the constant term form one side of the equation to other side, the sign changes from +ve to -ve.
Therefore, the general form is given as 2x+y-6 = 0.
Given the graph, we need to look for the equation of the line using the linear equation since the plot is obviously a line.
To do that, we need two points. The simplest points to locate are the two points that converges the x and y axes which are (3,0) and (4,0), respectively. Now we apply the linear equation formulation:
y = mx+b
First, we need to get the slope.
m = (y2-y1)/(x2-x1)
m = (4-0)/(0-3)
m = -4/3
Since we know the slope, we need to look for the b which is also the y-intercept or the point at which x = 0.
So at x = 0, which point or value at y-axis hits with the line? It is the point (0,4).
Therefore, b = 4.
Completing the equation,
y = -(4/3)x + 4
or we can write it as
4x + 3y = 12.
Now to know which of the choices is correct, we simply assign values and see for ourselves which is true.
Let x = 2, so y = 2
4(2) + 3y = 12
8 < 12
If you assign more values, you will notice that 4x + 3y is always less than or equal to 12. Thus, the answer is letter a.
I can use the equation .28(m) to solve this problem. If we plug in our numbers, we will get .28(315). This will give us 88.2. 88.2 is $88.2 dollars. Therefore, it costs him $88.2 dollars a week.
True!
Two shapes are congruent if when turning, flipping or sliding one shape it can become another. This problem is illustrated in the Figure below. So, you can see that we have two triangles ΔJKL and ΔPQR. As you can see:
Given that two sides are equal to two other sides and one angle is equal to another one, then JL= PR. Accordingly, since all the sides are congruent, then the whole triangle JKL is congruent to PQR
