Simple way of finding the decimal value : -
=> 46/200
Divide numerator and denominator by 2
=23/100
As 100 is in denominator, shift decimal by 2, i.e
= 0.23
Answer = 0.23
Answer:
Explain the circumstances for which the interquartile range is the preferred measure of dispersion
Interquartile range is preferred when the distribution of data is highly skewed (right or left skewed) and when we have the presence of outliers. Because under these conditions the sample variance and deviation can be biased estimators for the dispersion.
What is an advantage that the standard deviation has over the interquartile range?
The most important advantage is that the sample variance and deviation takes in count all the observations in order to calculate the statistic.
Step-by-step explanation:
Previous concepts
The interquartile range is defined as the difference between the upper quartile and the first quartile and is a measure of dispersion for a dataset.

The standard deviation is a measure of dispersion obatined from the sample variance and is given by:

Solution to the problem
Explain the circumstances for which the interquartile range is the preferred measure of dispersion
Interquartile range is preferred when the distribution of data is highly skewed (right or left skewed) and when we have the presence of outliers. Because under these conditions the sample variance and deviation can be biased estimators for the dispersion.
What is an advantage that the standard deviation has over the interquartile range?
The most important advantage is that the sample variance and deviation takes in count all the observations in order to calculate the statistic.
Answer:
Shifts it up c units.
Step-by-step explanation:
The '+ c' will move the whole graph upwards c units.
Answer:
35.8
Step-by-step explanation:
= 358
We know that our answer can never be greater than 358 since the dividend
is 340.1 and the divisor is 9.5;
Also,
Both values are to one decimal places and we can use this to solve the problem;
9 can divide 340 in about 37 place with a remainder of 7,
So, it is appropriate to make the solution 35.8
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