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gulaghasi [49]
3 years ago
13

The diagram shows the contents of a jar of marbles. You select two marbles at random. One marble is drawn and not replaced. Then

a second marble is drawn. What is the probability of selecting a red marble and then another red marble?
A) 3/64
B) 1)4
C) 1/20
D) 1/30
( there are 7 blue marbles, 5 green marbles, and 4 red marbles)
Mathematics
2 answers:
olganol [36]3 years ago
7 0
Since these are dependant, it is 4/16 times 3/15 since you took one out and did not replace. so C, 1/20
hoa [83]3 years ago
6 0

Answer:

Option C is the answer.

Step-by-step explanation:

There are some marbles in a jar

Blue -  7  marbles

Green -  5 marbles

Red  - 4 marbles

Total = 16 marbles

You selected two marbles at random without replacing any.

So the probability that first marble drawn is red = \frac{4}{16}

Now without replacing you selected another marble, So the probability that second marble is red = \frac{3}{15}

P_{1} = \frac{4}{16}

P_{2} =  \frac{3}{15}

P = \frac{4}{16} × \frac{3}{15} = \frac{1}{20}

The probability of selecting a red marble and then another red marble is

\frac{1}{20}.

Option C is the answer.

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