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gulaghasi [49]
3 years ago
13

The diagram shows the contents of a jar of marbles. You select two marbles at random. One marble is drawn and not replaced. Then

a second marble is drawn. What is the probability of selecting a red marble and then another red marble?
A) 3/64
B) 1)4
C) 1/20
D) 1/30
( there are 7 blue marbles, 5 green marbles, and 4 red marbles)
Mathematics
2 answers:
olganol [36]3 years ago
7 0
Since these are dependant, it is 4/16 times 3/15 since you took one out and did not replace. so C, 1/20
hoa [83]3 years ago
6 0

Answer:

Option C is the answer.

Step-by-step explanation:

There are some marbles in a jar

Blue -  7  marbles

Green -  5 marbles

Red  - 4 marbles

Total = 16 marbles

You selected two marbles at random without replacing any.

So the probability that first marble drawn is red = \frac{4}{16}

Now without replacing you selected another marble, So the probability that second marble is red = \frac{3}{15}

P_{1} = \frac{4}{16}

P_{2} =  \frac{3}{15}

P = \frac{4}{16} × \frac{3}{15} = \frac{1}{20}

The probability of selecting a red marble and then another red marble is

\frac{1}{20}.

Option C is the answer.

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Sindrei [870]
If i did the math correctly one number is 50
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And we need a number that has more than four factors and is greater than 25.
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50has six factors and is greater than 25.

4 0
3 years ago
1.
olchik [2.2K]
To solve this we are going to use the future value of annuity ordinary formula: FV=P[ \frac{(1+ \frac{r}{n} )^{kt} -1}{ \frac{r}{n} } ]
where
FV is the future value
P is the periodic payment
r is the interest rate in decimal form
n is the number of times the interest is compounded per year
k is the number of payments per year
t is the number of years

We know for our problem that P=6200 and t=5. To convert the interest rate to decimal form, we are going to divide the rate by 100%:
r= \frac{6}{100} =0.06
Since the deposit is made semiannually, it is made 2 times per year, so k=2.
Since the type of the annuity is ordinary, payments are made at the end of each period, and we know that we have 2 periods, so n=2.
Lets replace the values in our formula:

FV=P[ \frac{(1+ \frac{r}{n} )^{kt} -1}{ \frac{r}{n} } ]
FV=6200[ \frac{(1+ \frac{0.06}{2} )^{(2)(5)} -1}{ \frac{0.06}{2} } ]
FV=71076.06

We can conclude that the correct answer is <span>$71,076.06</span>
8 0
3 years ago
In a school, 60% of the students are boys. if the number of girls is 120, what is the number of boys in that school?
Luden [163]
There are 180 boys in the school.
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4 0
3 years ago
<img src="https://tex.z-dn.net/?f=%203log_%7B3%7D%285%29%20%20%5Ctimes%20%20log_%7B3%7D%284%20%29%20" id="TexFormula1" title=" 3
olga nikolaevna [1]

Answer:

log3 (500)

Step-by-step explanation:

3 log3 (5) * log3(4)

We know that a log b(c) = log b(c^a)

log3 (5)^3 * log3(4)

We know that log a(b) * log a (c) = loga( b*c)

log3 ((5)^3 * 4)

log3 (125*4)

log3 (500)

8 0
3 years ago
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