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Marina86 [1]
3 years ago
15

Special Right Triangles: Decimal Answer ! What’s H and C ?! Help me please?! Round to the nearest tenth.

Mathematics
1 answer:
lesantik [10]3 years ago
8 0

Answer:

h = 1.41

c = 3.46

Step-by-step explanation:

See the triangles diagram attached.

For the first triangle, Base = h, Hypotenuse = 2 and the angle between base and hypotenuse is 45°.

Therefore, \cos 45 = \frac{\textrm {Base}}{\textrm {Hypotenuse}} = \frac{h}{2}

⇒ h = 2 \cos 45 = \frac{2}{\sqrt{2} } = \sqrt{2} = 1.414 = 1.41 (Answer)

{Rounded to the nearest tenth}

Again in the second triangle, Perpendicular = c, Hypotenuse = 4 and the angle between base and hypotenuse is 60°.

Therefore, \sin 60 = \frac{\textrm {Perpendicular}}{\textrm {Hypotenuse}} = \frac{c}{4}

⇒ c = 4 \sin 60 = \frac{4 \times \sqrt{3} }{2} = 2\sqrt{3} = 3.46 (Answer)

{Rounded to the nearest tenth}

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Answer:

38.81cm³

Step-by-step explanation:

Volume of a sphere = 4/3πr³

Diameter is 4.2

radius= 4.2/2 = 2.1 or 21/10

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3 0
3 years ago
According to records from 50 years, there is a 2/3 chance of June temperatures being above 80 F. Azul needs to find the probabil
Brrunno [24]

Record of june temperature of last 50 years

Probability of June temperature being above 80° F from last 50 years

                      =\frac{2}{3}

It means , out of 30 days ,there are  only 20 days , in which temperature is above 80°F.

⇒Probability that it will be above 80° F for 20 or more days this June

                =\frac{20+x}{30}  

where, x is the number of extra days after 20 days in month of june, when temperature is above 80°F.

Value of this Probability will be in between

                \frac{2}{3}\leq P \leq 1  

Now, what Azul wants

 To find the probability that it will be above 80° F for 20 or more days this June.

The Simulation given is

  ⇒There are 30 days in June. If we use a number cube with the numbers 1-6 and assign 1-4 as a temperature above 80° F and 5-6 as a temperature 80° F or below.

Total number of numbers on number cube ={1,2,3,4,5,6}

Favorable Outcome={1,2,3,4}=Temperature above 80° F

Temperature 80° F or below ={5,6}

⇒Probability of getting number {1,2,3,4} on the number cube when rolled once,that is Temperature above 80° F

        =\frac{4}{6}\\\\=\frac{2}{3}

⇒Probability of getting number {5,6} on the number cube when rolled once, that is Temperature 80° F or below

        =\frac{2}{6}\\\\=\frac{1}{3}

This is Incorrect Simulation, as there are chances that , there can be more than 20 days out of 30 days when Temperature goes above 80° F.But Here we have got Probability of temperature being above 80° F for 20 days only, not more than 20 days, which is =\frac{2}{3}

Not,a number

    \frac{2}{3}< \text{Probability} \leq 1.    

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