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3 years ago

Are ratios 7/4 and 42/24 equivalent

Mathematics

2 answers:

lara31 [8.8K]3 years ago

5 0

Step-by-step explanation:

they're equivalent

42 and 24 are multiple of 6

so 42/24

42/6 is 7

24/6 is 4

fraction is 7/4 so YES

babymother [125]3 years ago

4 0

42/24 = 42/24 or 7/4 = 42/24 so yes

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*****50 POINTSSSS*****

defon

Answer:

<h3>Given</h3>

m∠REG = 78°
mAR = 46°
ER ≅ GA

<h3>Solution</h3>

m∠GAR = 180° - m∠REG = 180° - 78° = 102° (supplementary angles sum to 180°)
m∠TAR = 1/2mAR = 1/2(46°) = 23° (tangent chord angle is half the size of intercepted arc)
m∠GAN = 180° - (m∠TAR + m∠GAR) = 180° - (23° + 102°) = 55° (straight angle is 180°)
mAG = 2m∠GAN = 2(55°) = 110°
mRE = mAG = 110° (as ER ≅ GA)
mGE = 360° - (mAG + mAR + mRE) = 360° - (110° + 46° + 110°) = 94° (full circle is 360°)

6 0

3 years ago

I need help quick. I will mark as brainliest.

Dimas [21]

Answer:

The slope is -5x

Step-by-step explanation:

To find the slope, you do rise/run. So to get from one point to the other, you would move 5 units down, and 1 unit to the right.

It can be written as -5/1 or -5.

Hope this helps!

8 0

3 years ago

What is the square root of 9

Ber [7]

Answer: √9 = 3

Verification:

= 3 * 3
=> 9

4 0

2 years ago

GJ is a midsegment of triangle DEF, and HK is a midsegment of triangle GFJ. What is the length of HK?

loris [4]

Answer:

Option B) 4 centimeters

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

Find the value of n

we know that

a) GJ is a midsegment of triangle DEF

then

G is the midpoint segment DF and J is the midpoint segment EF

DG=GF and EJ=JF

b) HK is a midsegment of triangle GFJ

then

H is the midpoint segment GF and K is the midpoint segment JF

GH=HF and JK=KF

In this problem we have

HF=7 cm

GH=7 cm

GF=GH+HF ----> by addition segment postulate

GF=7+7=14 cm

Remember that

DG=GF

substitute the given values

$2n-1=14$

solve for n

$2n=14+1$

$2n=15$

$n=7.5\ cm$

step 2

Find the length of GJ

we know that

The <u><em>Midpoint Theorem</em></u> states that the segment joining two sides of a triangle at the midpoints of those sides is parallel to the third side and is half the length of the third side

$GJ=\frac{1}{2}DE$