Since triangle DEF = triangle JKL, m<D = m<J, m<E = m<K, m<F = m<L.
m<F = m<L = 90 degrees
m<K = m<E = 5(m<D)
but m<E + m<D = 90 degrees [right angled triangle]
5(m<D) + m<D = 90 degrees
6(m<D) = 90 degrees
m<D = 90 / 6 = 15 degrees.
Yes I’m sorry but I’m sorry I’m texting back to my sister in
Step-by-step explanation:
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Answer:
- b/a
- 16a²b²
- n¹⁰/(16m⁶)
- y⁸/x¹⁰
- m⁷n³n/m
Step-by-step explanation:
These problems make use of three rules of exponents:

In general, you can work the problem by using these rules to compute the exponents of each of the variables (or constants), then arrange the expression so all exponents are positive. (The last problem is slightly different.)
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1. There are no "a" variables in the numerator, and the denominator "a" has a positive exponent (1), so we can leave it alone. The exponent of "b" is the difference of numerator and denominator exponents, according to the above rules.

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2. 1 to any power is still 1. The outer exponent can be "distributed" to each of the terms inside parentheses, then exponents can be made positive by shifting from denominator to numerator.

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3. One way to work this one is to simplify the inside of the parentheses before applying the outside exponent.

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4. This works the same way the previous problem does.

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5. In this problem, you're only asked to eliminate the one negative exponent. That is done by moving the factor to the numerator, changing the sign of the exponent.

Answer:
Result:
Step-by-step explanation:
Given
The parallelogram DEFG
DE = 6x-12
FG = 2x+36
EF = 4y
DG = 6y-42
We know that the opposite sides of a parallelogram are equal.
As DE and FG are opposite sides, so
DE = FG
substituting DE = 6x-12 and FG = 2x+36 in the equation
6x-12 = 2x+36
6x-2x = 36+12
simplifying
4x = 48
dividing both sides by 4
4x/4 = 48/4
x = 12
Therefore,
The value of x = 12
Also, EF and DG are opposite sides, so
EF = DG
substituting EF = 4y and DG = 6y-42 in the equation
4y = 6y-42
switching sides
6y-42 = 4y
6y-4y = 42
2y = 42
dividing both sides by 2
2y/2 = 42/2
y = 21
Therefore,
The value of y = 21
Result: