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zzz [600]
3 years ago
7

Please help

Mathematics
1 answer:
mafiozo [28]3 years ago
4 0

Answer:

Easy it's a right hand child

Step-by-step explanation:

Because if both husband and wife both have right hands. And it's 10% chance the child will be left handed. Then it's possible that the child is going to be a right hand.

You might be interested in
2. Simplify ((–3)2)3
Nat2105 [25]

Answer:

-18

Step-by-step explanation:

((-3)2)3

First, you multiply -3 and 2 which equals  -6

-3·2=-6

Then, you multiply -6 and 3 which equals  -18

-6·3=-18

6 0
3 years ago
What is this math problem x²+9×+14=0
WINSTONCH [101]
x^2+9x+14=0\\\\ x_{1}=\frac{-b-\sqrt{b^2-4ac} }{2a}=\frac{-9-\sqrt{9^2-4*1*14 } }{2 }=\frac{-9-\sqrt{81-56 } }{2 }= \frac{-9-\sqrt{25 } }{2 }=\\\\=\frac{-9-5 }{2 }=\frac{-14 }{2 }= -7\\\\ x_{2}=\frac{-b+\sqrt{b^2-4ac} }{2a}=\frac{-9+\sqrt{9^2-4*1*14 } }{2 }= \frac{-9+5 }{2 }=\frac{- 4 }{2 }= -2


5 0
4 years ago
1
Kazeer [188]

Answer:

D

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = \frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

with (x₁, y₁ ) = (- 4, 29) and (x₂, y₂ ) = (0, 28) ← 2 ordered pairs from the table

m = \frac{28-29}{0+4} = - \frac{1}{4}

The line crosses the y- axis at (0, 28 ) ⇒ c = 28

y = - \frac{1}{4} x + 28 ← equation of line → D

8 0
4 years ago
1. The zeros of a quadratic relation are 3 and The second differences are positive
nata0808 [166]

Answer:

The optimal, vertex, value will be a minimum

Step-by-step explanation:

The given zeros of the quadratic relation are 3 and 3

The sign of the second differences of the quadratic relation = Positive

Whereby the two zeros are the same as x = 3, we have that the point 3 is the optimal value or vertex (the repeated point in the graph of the quadratic relation) of the quadratic relation

Whereby, the table of values for the quadratic relation from which the second difference is found starts from x = 3, we have;

To the right of the coordinate points of the zeros of the quadratic relation, the positive second difference in y-values gives as x increases, y increases which gives a positive slope

By the nature of the quadratic graph, the slope of the line to the left of the coordinate point of the zeros of the quadratic relation will be of opposite sign (or negative). The quadratic relation is cup shaped and the zeros, therefore, the optimal value will be a minimum of the quadratic relation

8 0
3 years ago
Enter a negative that is great than -10
xxMikexx [17]
-9, -8, -7, etc. With positive numbers, greater value is determined by raising the number. However, with negatives, the smaller the number it is (aka the closer it is to 0), the greater value it has. This causes numbers like -1 to be greater than -10. Hope this helps :)
7 0
3 years ago
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