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Firdavs [7]
3 years ago
13

Rewrite in simplest terms: -(2c + 8) + 8c

Mathematics
1 answer:
garik1379 [7]3 years ago
6 0

Answer:

6c-8

Step-by-step explanation:

We have:

-(2c+8)+8c=

-2c-8+8c=\\

6c - 8

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Write one digit on each side of 36 to make a four-digit multiple of 36. How many different solutions does this problem have?
vaieri [72.5K]

9514 1404 393

Answer:

  3 solutions: 1368, 5364, 9360

Step-by-step explanation:

In order to be divisible by 36, the number must be divisible by 9 and by 4. The number will be divisible by 9 if the sum of its digits is divisible by 9. 36 already has a digit sum of 9, so the two added digits must sum to 9.

The number will be divisible by 4 if the least-significant digit is a multiple of 4. That is, it must be 0, 4, or 8. Then the corresponding most-significant digits must be 9, 5, or 1.

The three solutions are ...

  1368 = 38 · 36

  5364 = 149 · 36

  9360 = 260 · 36

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3 years ago
The absolute ______ of 2 is 2.<br> 1.) absolute value <br> 2.)sign<br> 3.)opposite
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The absolute value of 2 is 2
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3 years ago
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Alex_Xolod [135]
C is your answer…………
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3 years ago
Ví dụ 1.5. Một người đi mua hàng 3 lần. Xác suất lần đầu mua được hàng tốt là 0,7.
vodka [1.7K]

Answer:

a) 0.50575,

b) 0.042

Step-by-step explanation:

Example 1.5. A person goes shopping 3 times. The probability of buying a good product for the first time is 0.7.

If the first time you can buy good products, the next time you can buy good products is 0.85;  (I interpret this as, if you buy a good product, then the next time you buy a good product is 0.85).

And if the last time I bought a bad product, the next time I bought a good one is  0.6. Calculate the probability that:

a) All three times the person bought good goods.

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P(Good on 1st shopping event) *P(Good on 2nd shopping event | Good on 1st shopping event) * P(Good on 3rd shopping event | 1st and 2nd shopping events yield Good) =

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b) Only the second time that person buys a bad product.

P(Good on 1st shopping event AND Bad on 2nd shopping event AND Good on 3rd shopping event) =

P(Good on 1st shopping event) *P(Bad on 2nd shopping event | Good on 1st shopping event) * P(Good on 3rd shopping event | 1st is Good and 2nd is Bad shopping events) =

(0.7)(1-0.85)(1-0.6) =

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3 years ago
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