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2 years ago

12

Samantha has 23 strawberries and wants to put 4 strawberries into each bowl. How many bowls can Samantha put exactly 4 strawberr

ies into? A. 3 B. 4 C. 5 D. 6

1 answer:

Bogdan [553]2 years ago

8 0

4 cannot go into 23 equally BUT! if you do 23 divided by 4 you'll get 5.75 which rounds up to 6. So on average she'll need 6 bowls for her 23 strawberries.

Edit: It should be 5 bowls because if she wants to put an equal amount of strawberries into her bowls it should be 5.

Hope it helped. :)

<em>~Noodles~</em>

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Answer:

(a+2)(b+2) = 4

Step-by-step explanation:

We are given the following quadratic equation:

$2x^2-3x-6=0$

Let a a and b be the solution of the given quadratic equation.

Solving the equation:

$2x^2-3x-6=0\\\text{Using the quadratic formula}\\\\x = \dfrac{-b \pm \sqrt{b^2-4ac}}{2a}\\\\\text{Comparing the equation to }ax^2 + bx + c = 0\\\text{We have}\\a = 2\\b = -3\\c = -6\\x = \dfrac{3\pm \sqrt{9-4(2)(-6)}}{4} = \dfrac{3\pm \sqrt{57}}{4}\\\\a = \dfrac{3+\sqrt{57}}{4}, b = \dfrac{3-\sqrt{57}}{4}$

We have to find the value of (a+2)(b+2).

Putting the values:

$(a+2)(b+2)\\\\=\bigg(\dfrac{3+\sqrt{57}}{4}+2\bigg)\bigg(\dfrac{3-\sqrt{57}}{4}+2\bigg)\\\\=\bigg(\dfrac{11+\sqrt{57}}{4}\bigg)\bigg(\dfrac{11-\sqrt{57}}{4}\bigg)\\\\=\dfrac{121-57}{156} = \dfrac{64}{16} = 4$

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2 years ago

Simplify (7ab)squared 0 <br>A) 7<br> B) 1 <br>C) 7ab <br>D)0

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Step-by-step explanation:

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3 years ago

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2 years ago

A company is constructing an open-top, square-based, rectangular metal tank that will have a volume of 49 cubic feet. What dime

yawa3891 [41]

Answer:

b = 4.6 ft

h = 2.3 ft

Step-by-step explanation:

The volume of the tank is given by:

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Where 'b' is the length of the each side of the square base, and 'h' is the height of the tank.

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3 years ago

The length of a rectangular flower bed is 2ft longer than the width. If the area is 6ft, then what are the exact length and widt

Marizza181 [45]

Answer:

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$length=-1+\sqrt{7}+2$

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Approximate dimensions:

$width=1.64575ft$

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$length=3.64575ft$

Step-by-step explanation:

Let's assume width of rectangle is w ft

The length of a rectangular flower bed is 2ft longer than the width

so,

length =w+2

$L=w+2$

now, we can find area

$A=L\times W$

now, we can plug it

$A=(w+2)\times w$

$A=w^2+2w$

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so, we can set it equal

and then we can solve for w

$w^2+2w=6$

$w^2+2w-6=0$

we can use quadratic formula

$ax^2+bx+c=0$

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

now, we can compare and find a,b and c

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we know that dimension can never be negative

so, we will only consider positive value

Exact dimensions:

$width=-1+\sqrt{7}$

$length=-1+\sqrt{7}+2$

$length=1+\sqrt{7}$

Approximate dimensions:

$width=1.64575ft$

$length=1.64575+2$

$length=3.64575ft$

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3 years ago