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AysviL [449]
2 years ago
5

A new cell tower is being constructed and needs a guy-wire connected 180 feet up the tower and it needs to make an angle of 52°

with the ground. What length does the wire need to be?
Mathematics
1 answer:
nevsk [136]2 years ago
6 0

Answer:

228.42 ft

Step-by-step explanation:

To solve for this question, we would be applying the Trigonometric function of Sine.

Sin theta = Opposite/Hypotenuse

Theta = 52°

Opposite = 180ft

Hypotenuse = Length of the wire = x

Hence:

sin 52 = 180/x

x = 180/sin 52

x = 228.42327871 ft

Approximately = 228.42 ft

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Mr.Smith is building a fence around his garden. The length is 3 feet longer than twice the width. The perimeter is 72 feet. Part
olga nikolaevna [1]

Step-by-step explanation:

A.C

B.2w + 2(w + 3) = 72

2w + 2w + 6 = 72

4w + 6 = 72

4w = 72 - 6

4w = 66

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5 0
3 years ago
Please help me with this question
san4es73 [151]

Step-by-step explanation:

Given: f'(x) = x^2e^{2x^3} and f(0) = 0

We can solve for f(x) by writing

\displaystyle f(x) = \int f'(x)dx=\int x^2e^{2x^3}dx

Let u = 2x^3

\:\:\:\:du=6x^2dx

Then

\displaystyle f(x) = \int x^2e^{2x^3}dx = \dfrac{1}{6}\int e^u du

\displaystyle \:\:\:\:\:\:\:=\frac{1}{6}e^{2x^3} + k

We know that f(0) = 0 so we can find the value for k:

f(0) = \frac{1}{6}(1) + k \Rightarrow k = -\frac{1}{6}

Therefore,

\displaystyle f(x) = \frac{1}{6} \left(e^{2x^3} - 1 \right)

5 0
2 years ago
Can 18 feet and 5 yards be expressed as a ratio in simplest form
Nuetrik [128]
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7 0
3 years ago
Read 2 more answers
Please help i dont understand what its asking
Arisa [49]

Multiply both the numerator and denominator by 2+\sqrt3, which is called the "conjugate" of 2-\sqrt3:

\dfrac{5+\sqrt3}{2-\sqrt3}\cdot\dfrac{2+\sqrt3}{2+\sqrt3}

Why do we pick this number? Recall the difference of squares factorization:

a^2-b^2=(a-b)(a+b)

Now replace a=2 and b=\sqrt3. Then

(2-\sqrt3)(2+\sqrt3)=2^2-(\sqrt3)^2=4-3=1

So in your fraction, you end up with

\dfrac{5+\sqrt3}{2-\sqrt3}=\dfrac{(5+\sqrt3)(2+\sqrt3)}1=(5+\sqrt3)(2+\sqrt3)

Finally, just expand the product.

(5+\sqrt3)(2+\sqrt3)=10+7\sqrt3+(\sqrt3)^2=\boxed{13+7\sqrt3}

7 0
2 years ago
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