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Andrej [43]
3 years ago
8

A nature museum has 2008 specimens of early birds, some with 222 wings and some with 444 wings. The specimens have a total of 40

384 wings.How many specimens are there with each number of wings?
Mathematics
1 answer:
ludmilkaskok [199]3 years ago
5 0

Let's assume

number of birds with 2 wings is x

number of birds with 4 wings is y

A nature museum has 2008 specimens of early birds

so,

x+y=2008

Total of wings of 2 wings bird =2x

Total of wings of 4 wings bird =4y

The specimens have a total of 4384 wings

so, we get

2x+4y=4384

we can divide both sides by 2

x+2y=2192

so, we get system of equations as

x+y=2008

x+2y=2192

we can solve for x and y

We can subtract both equations

2008-y+2y=2192

y=184

x=2008-184

x=1824

y=184,\:x=1824

so,

number of birds with 2 wings is 1824

number of birds with 4 wings is 184.............Answer



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3 years ago
I don’t know how to do this
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