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Fofino [41]
3 years ago
9

What percent of 480 is 160? A. 0.3% B. 3% C. 30% D. 33.3% E. 300%

Mathematics
1 answer:
Kaylis [27]3 years ago
4 0
Answer: E

Explanation: If you are using a calculator, simply enter 480÷160×100 which will give you 300 as the answer.
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IL COSL al we creeree viall
kakasveta [241]

Answer:

<em>In the next year, Anthony worked 2,084 hours</em>

Step-by-step explanation:

Anthony worked 1,697 hours in 2010.

We also know Anthony worked 22.8% more hours than in 2010.

The problem requires to calculate how much did Anthony work in the next year.

It can be calculated as follows:

Take 22.8% of 1,697:

22.8 * 1,697 / 100 = 386.916\approx 387\ hours

Now calculate by adding it to the original number of hours:

1,697 + 387 = 2,084 hours

In the next year, Anthony worked 2,084 hours

8 0
3 years ago
If f(x) and f⁻¹(x) are inverse functions of each other and f(x)=2x+5, what is f⁻¹(8)?
dexar [7]

Answer:

3/2.

Step-by-step explanation:

f(x)=2x+5   Finding the inverse:

y = 2x + 5

2x = y - 5

x = (y - 5)/2

So the inverse f-1(x) = (x - 5)/2

and f-1(8) = (8-5)/2

= 3/2.

3 0
3 years ago
How do you solve 0.75(8+e)=2−1.25e ?
mash [69]
Distribute first.
.75 times 8 + .75 times e, which is 6+.75e = 2-1.25e
Then subtract 2 from both sides,
4+.75n=-1.25e
Next subtract .75 from both sides,
4=-2e
Divide both sides by -2, and you will get e= -2. Hope this helps!

6 0
3 years ago
Como soluciono equaciones =0​
Rom4ik [11]

Step-by-step explanation:

ما زلت لا أستطيع أن أخبرني بما تحاول أن تخبرني به ولد أو بنت آسف على تحمله

8 0
3 years ago
An oil tank has to be drained for maintenance. The tank is shaped like a cylinder that is 3ft long with a diameter of 2.2 ft . S
Contact [7]

4 minutes 34 seconds will takes to empty the tank, if the starts completely full and oil drained at a rate of 2.5 ft^{3} per minute.

Step-by-step explanation:

              The given is,

                         Tank is shaped like a cylinder that is 3 ft long with a diameter of 2.2 ft.

                          Oil drained at a rate of 2.5 ft^{3} per minute.

Step:1

       Time taken to dry the oil tank is,

                           T   = \frac{Volume of oil}{Oil drain rate}  ....................................(1)

Step:2

      Volume of the oil is,

                           V = \pi  r^{2} h.................................................(2)

      Where, r - Radius of Cylinder

                             r = \frac{d}{2}

                             r = \frac{2.2}{2}

                             r = 1.1 ft

      From eqn (1),

                        V =  \pi × 1.1^{2} × 3

                           = 11.40398 ft^{3}

Step:3

     From equation (1)

                           = \frac{11.40398}{2.5}

                           = 4.56

                           = 4.56 minutes

                      T  = 4 minutes 34 seconds

Result:

      Time taken to dry the oil tank is 4 minutes 34 seconds, if a cylinder is 3 ft long with a diameter of 2.2 ft and oil is drained at a rate of 2.5ft^3 per minute.

4 0
2 years ago
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