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JulsSmile [24]
2 years ago
6

What is the value of 12(8+9)​

Mathematics
2 answers:
Sergeu [11.5K]2 years ago
4 0

Answer:

204

Step-by-step explanation:

rjkz [21]2 years ago
4 0

Answer:

your answer would be 204  

Step-by-step explanation:

12(8+9)  

8+9=17

12(17)

=204

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Megan wants to change her Internet Service Provider.
Lera25 [3.4K]

Good for Megan............

4 0
2 years ago
Round off then estimate 18.9*5.2
Nataly [62]
18.9 rounded is 19
5.2 rounded is 5

19 * 5 = 95
7 0
3 years ago
Lucy's fish tank has 14 liters of water in it. She plans to add 5 liters per minute until the tank has at least 49 liters. What
Vikentia [17]

Answer:

Step-by-step explanation:

14 + 5t > = 49 (thats a greater then or equal sign)

5t > = 49 - 14

5t > = 35

t > = 35/5

t > = 7 <===

3 0
3 years ago
Solve for x. Round to the nearest tenth if necessary.
timofeeve [1]

Answer: 41.1

Step-by-step explanation:

To find the value of x, we need to use SOH-CAH-TOA. SOH-CAH-TOA is since, cosine, and tangent. The O, A, H stands for opposite, adjacent, and hypotenuse respectively.

Looking at the figure, we see 47°. The labelled angles are adjacent and the hypotenuse. Therefore, we use CAH or cosine.

cos(47)=\frac{28}{x}             [multiply both sides by x]

xcos(47)=28           [divide both sides by cos(47)]

x=\frac{28}{cos(47)}

When we plug that into a calculator, we get x=41.1.

5 0
2 years ago
Read 2 more answers
(I've been trying to figure this out for 3 days and I really need help)
liq [111]

Check the picture below.

since the diameter of the cone is 6", then its radius is half that or 3", so getting the volume of only the cone, not the top.

1)

\bf \textit{volume of a cone}\\\\ V=\cfrac{\pi r^2 h}{3}~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ r=3\\ h=4 \end{cases}\implies V=\cfrac{\pi (3)^2(4)}{3}\implies V=12\pi \implies V\approx 37.7

2)

now, the top of it, as you notice in the picture, is a semicircle, whose radius is the same as the cone's, 3.

\bf \textit{volume of a sphere}\\\\ V=\cfrac{4\pi r^3}{3}~~ \begin{cases} r=radius\\[-0.5em] \hrulefill\\ r=3 \end{cases}\implies V=\cfrac{4\pi (3)^3}{3}\implies V=36\pi \\\\\\ \stackrel{\textit{half of that for a semisphere}}{V=18\pi }\implies V\approx 56.55

3)

well, you'll be serving the cone and top combined, 12π + 18π = 30π or about 94.25 in³.

4)

pretty much the same thing, we get the volume of the cone and its top, add them up.

\bf \stackrel{\textit{cone's volume}}{\cfrac{\pi (3)^2(8)}{3}}~~~~+~~~~\stackrel{\stackrel{\textit{half a sphere}}{\textit{top's volume}}}{\cfrac{4\pi 3^3}{3}\div 2}\implies 24\pi +18\pi \implies 42\pi ~~\approx~~131.95~in^

8 0
3 years ago
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