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sineoko [7]
3 years ago
14

Explain how you could use a number line to show that -4 + 3 and 3 + (-4) have the same value

Mathematics
1 answer:
iogann1982 [59]3 years ago
6 0
Find (-4) on the number line and move 3 to the right.  You will end up at (-1).

Find (3) on the number line and move 4 to the left.  You will end up at the same value of (-1).
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Step-by-step explanation:

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What is two hundred sixty-five thousandths in standard form?
Debora [2.8K]

Answer:

10^-1*2.65

Step-by-step explanation:

two hundred sixty-five thousandths= 0.265

We need a number between 1 and 10, to do the multiplication in standard form, so 0.265 turns into 2.65.

Because 2.65 becomes, smaller we use a negative power. We only move the decimal place once to the left, so we would multiply 2.65 by 10^1.

10^-1*2.65=0.265

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Step-by-step explanation:

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Step-by-step explanation:

3 0
3 years ago
A statistics student wants to compare his final exam score to his friend's final exam score from last year; however, the two exa
yarga [219]

Answer:

z= \frac{85-70}{10}=1.5

z= \frac{45-35}{5}=2

So then the correct answer for this case is:

B) Our student, Z= 1.50; his friend, Z=2.00.

Step-by-step explanation:

Assuming this complete question:

A statistics student wants to compare his final exam score to his friend's final exam score from last year; however, the two exams were scored on different scales. Remembering what he learned about the advantages of Z scores, he asks his friend for the mean and standard deviation of her class on the exam, as well as her final exam score. Here is the information:

Our student: Final exam score = 85; Class: M = 70; SD = 10.

His friend: Final exam score = 45; Class: M = 35; SD = 5.

The Z score for the student and his friend are:

A) Our student, Z= -1.07; his friend, Z= -1.14.

B) Our student, Z= 1.50; his friend, Z=2.00.

C) Our student, Z= 1.07; his friend, Z= -1.14.

D) Our student, Z= 1.07; his friend, Z= 1.50

Step-by-step explanation:

Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

Solution

Let X the random variable that represent the scores for our student, and for this case we know that:

E(X)= \mu =70, SD_X=\sigma=10  

The z score is given by:

z=\frac{x-\mu}{\sigma}

If we use this we got:

z= \frac{85-70}{10}=1.5

Let Y the random variable that represent the scores for his friend, and for this case we know that:

E(Y)= \mu =35, SD_Y=\sigma=5  

The z score is given by:

z=\frac{y-\mu}{\sigma}

If we use this we got:

z= \frac{45-35}{5}=2

So then the correct answer for this case is:

B) Our student, Z= 1.50; his friend, Z=2.00.

3 0
3 years ago
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