Question

You're a newly appointed Engineer in APE Chemical Sdn Bhd. and your first task is to design a 0.35m vessel to be used to store saturated vapor ethanol at 480°C and 6000 kPa. For these conditions, analyze (6) The molar volume of the saturated vapor ethanol. . (15 marks) (6) The mass of the saturated vapor ethanol in the vessel

Answer 1

Answer:

molar volume of vapor ethanol is $V = 1.043 \times 10^{-3} m^3/mol$

mass of ethanol is 15430.22 g

Explanation:

By using ideal gas equation

PV = nRT

Where P is pressure , R is gas constant

so, volume is

$V = \frac{RT}{P} = \frac{8.314\times (480+273)}{6000\times 10^3}$

$V = 1.043 \times 10^{-3} m^3/mol$

molar volume of vapor ethanol is

$V = 1.043 \times 10^{-3} m^3/mol$

b)

volume of vessel is given $0.35 m^3$

therefore total moles of ethanol in given vessel will be

$n =\frac{V_{vessel}}{V}$

$n =\frac{0.35}{1.043\times10^{-3}}$

n = 335.44 mol

we know that

mole is given as [/tex]n = \frac{mass}{moleculae weight}[/tex]

weight of ethanol is 46 g/mol

n\times 46 = mass

$335.44\times 46 = 15430.22 g$

mass of ethanol is 15430.22 g