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Mkey [24]
3 years ago
10

A colorless solution is known to contain one of these ions. Which ion is present if adding dilute HCl produces a white precipita

te that dissolves when the solution is warmed?
(A) Ag+
(B) Cu2+
(C) Hg22+(D) Pb2+
Chemistry
1 answer:
marta [7]3 years ago
4 0

Answer:

The correct answer is option D.

Explanation:

All the cations given belong to the group-1 cation and will give precipitate of their respective chlorides when HCl is added to their aqueous solution.

Ag^+(aq)+HCl(aq)\rightarrow AgCl(s)+H^+(aq)

Cu^{2+}+(aq)+2HCl(aq)\rightarrow CuCl_2(s)+2H^+(aq)

Hg_{2}^{2+}+(aq)+2HCl(aq)\rightarrow Hg_2Cl_2(s)+2H^+(aq)

Pb^{2+}+(aq)+2HCl(aq)\rightarrow PbCl_2(s)+2H^+(aq)

All the precipitates are insoluble in cold water but out of all these only lead(II) chloride is soluble in warm water.

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Explanation:

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8 0
4 years ago
A student collects 450. mL of HCl gas at a pressure of 101 kPa and a temperature of 17ºC. What would the volume of the gas be if
xenn [34]

Answer:

449 mL

Explanation:

Using Ideal gas equation for same mole of gas as

\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}

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V₁ = 450 mL

V₂ = ?

P₁ = 101 kPa

P₂ = 104 kPa

T₁ = 17 ºC

T₂ = 25 ºC

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T₁ = (17 + 273.15) K = 290.15 K

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Using above equation as:

\frac {{P_1}\times {V_1}}{T_1}=\frac {{P_2}\times {V_2}}{T_2}

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V₂ = 449 mL

8 0
3 years ago
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