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Mkey [24]
3 years ago
10

A colorless solution is known to contain one of these ions. Which ion is present if adding dilute HCl produces a white precipita

te that dissolves when the solution is warmed?
(A) Ag+
(B) Cu2+
(C) Hg22+(D) Pb2+
Chemistry
1 answer:
marta [7]3 years ago
4 0

Answer:

The correct answer is option D.

Explanation:

All the cations given belong to the group-1 cation and will give precipitate of their respective chlorides when HCl is added to their aqueous solution.

Ag^+(aq)+HCl(aq)\rightarrow AgCl(s)+H^+(aq)

Cu^{2+}+(aq)+2HCl(aq)\rightarrow CuCl_2(s)+2H^+(aq)

Hg_{2}^{2+}+(aq)+2HCl(aq)\rightarrow Hg_2Cl_2(s)+2H^+(aq)

Pb^{2+}+(aq)+2HCl(aq)\rightarrow PbCl_2(s)+2H^+(aq)

All the precipitates are insoluble in cold water but out of all these only lead(II) chloride is soluble in warm water.

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What happens in a neutralization reaction?
mina [271]

Answer:

Answer is letter B

Explanation:

The first one is wrong because acids release H+, not bases.

The third one is wrong because the pH is exactly 7, not greater.

The last one is wrong because it is vague and does not fit a neutralization reaction.

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3 years ago
What is the answer to “An element is:”
Jobisdone [24]
A. A pure chemical substance consisting of one type of atom
8 0
2 years ago
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Urea, a compound formed in the liver, is one of the ways humans excrete nitrogen. The Lewis structure for urea is H N H H C H O
yanalaym [24]

Answer:

The nitrogens are both sp3 hybridized. Their  bonds are formed by sp overlaps. The carbon and oxygen are sp2 hybridized. The double bond with oxygen is produced by a sp2 overlap to form the sigma component and a probital overlap to form the pi component. The bonds with hydrogen are formed by sp2 overlaps.

Explanation:

5 0
3 years ago
A student placed 18.5 g of glucose (C6H12O6) in a volumetric flask, added enough water to dissolve the glucose by swirling, then
mamaluj [8]

Answer:

1.30464 grams of glucose was present in 100.0 mL of final solution.

Explanation:

Molarity=\frac{moles}{\text{Volume of solution(L)}}

Moles of glucose = \frac{18.5 g}{180 g/mol}=0.1028 mol

Volume of the solution = 100 mL = 0.1 L (1 mL = 0.001 L)

Molarity of the solution = \frac{0.1028 mol}{0.1 L}=1.028 mol/L

A 30.0 mL sample of above glucose solution was diluted to 0.500 L:

Molarity of the solution before dilution = M_1=1.208 mol

Volume of the solution taken = V_1=30.0 mL

Molarity of the solution after dilution = M_2

Volume of the solution after dilution= V_2=0.500L = 500 mL

M_1V_1=M_2V_2

M_2=\frac{M_1V_1}{V_2}=\frac{1.208 mol/L\times 30.0 mL}{500 mL}

M_2=0.07248 mol/L

Mass glucose are in 100.0 mL of the 0.07248 mol/L glucose solution:

Volume of solution = 100.0 mL = 0.1 L

0.07248 mol/L=\frac{\text{moles of glucose}}{0.1 L}

Moles of glucose = 0.07248 mol/L\times 0.1 L=0.007248 mol

Mass of 0.007248 moles of glucose :

0.007248 mol × 180 g/mol = 1.30464 grams

1.30464 grams of glucose was present in 100.0 mL of final solution.

4 0
3 years ago
The process in which liquid material is poured into a mold to form sculpture is called: carving casting modeling assemblage
Vika [28.1K]
The answer would be modeling, because craving is when you take a block of something and slice it t make something,and casting is when you put layers over layers to form a something. so the answer will be modeling.
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3 years ago
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