Question

Given that f(x) = 6x + 2 and g(x) = the quantity of 2x plus 4 divided by 5, solve for g(f(1)).

Answer 1

Answer:

Option c is correct.

the value of g(f(1)) is, 4

Step-by-step explanation:

Given the functions:

$f(x) = 6x+2$

$g(x) = \frac{2x+4}{5}$

We have to find the g(f(1):

$g(f(x)) = g(6x+2)$

Substitute 6x+2 in place of x in the function g(x) we have;

$g(f(x)) = g(6x+2) = \frac{2(6x+2)+4}{5}$

⇒$g(f(x)) = \frac{12x+4+4}{5} = \frac{12x+8}{5}$

Substitute x = 1 we have;

$g(f(1)) = \frac{12(1)+8}{5} = \frac{12+8}{5} = \frac{20}{5}=4$

Therefore, the value of g(f(1)) is, 4

Answer 2

The answer is 4! If you plug in the 1 for x in f(x), that gives you 8. Then you plug in f(x) into g(x), you get 4!