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telo118 [61]
3 years ago
7

A store plans to sell two different game consoles, the Wii and the xbox. The store’s wholesale price for the Wii is $250, and th

e store can sell one for $295. The xbox wholesale price is $400, and the store can sell it for $450. The stores marketing research indicates that the total monthly demand for game consoles will not exceed 250 units sold. The store’s financial manager doe not want to invest more than $70,000 in inventory costs for game consoles. Write the constraints and the objective formula.
Mathematics
1 answer:
Nimfa-mama [501]3 years ago
3 0

Answer:

hi just need points

Step-by-step explanation:

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Variable a is 4 more than variable b. Variable a is also 1 less than b. Which of the following pairs of equations best models th
Elis [28]
B=a+4 that is what the answer will be.
4 0
3 years ago
Suppose you pay a dollar to roll two dice. if you roll 5 or a 6 you Get your dollar back +2 more just like it the goal will be t
LiRa [457]

Answer:

(a)$67

(b)You are expected to win 56 Times

(c)You are expected to lose 44 Times

Step-by-step explanation:

The sample space for the event of rolling two dice is presented below

(1,1), (2,1), (3,1), (4,1), (5,1), (6,1)\\(1,2), (2,2), (3,2), (4,2), (5,2), (6,2)\\(1,3), (2,3), (3,3), (4,3), (5,3), (6,3)\\(1,4), (2,4), (3,4), (4,4), (5,4), (6,4)\\(1,5), (2,5), (3,5), (4,5), (5,5), (6,5)\\(1,6), (2,6), (3,6), (4,6), (5,6), (6,6)

Total number of outcomes =36

The event of rolling a 5 or a 6 are:

(5,1), (6,1)\\ (5,2), (6,2)\\( (5,3), (6,3)\\ (5,4), (6,4)\\(1,5), (2,5), (3,5), (4,5), (5,5), (6,5)\\(1,6), (2,6), (3,6), (4,6), (5,6), (6,6)

Number of outcomes =20

Therefore:

P(rolling a 5 or a 6)  =\dfrac{20}{36}

The probability distribution of this event is given as follows.

\left|\begin{array}{c|c|c}$Amount Won(x)&-\$1&\$2\\&\\P(x)&\dfrac{16}{36}&\dfrac{20}{36}\end{array}\right|

First, we determine the expected Value of this event.

Expected Value

=(-\$1\times \frac{16}{36})+ (\$2\times \frac{20}{36})\\=\$0.67

Therefore, if the game is played 100 times,

Expected Profit =$0.67 X 100 =$67

If you play the game 100 times, you can expect to win $67.

(b)

Probability of Winning  =\dfrac{20}{36}

If the game is played 100 times

Number of times expected to win

=\dfrac{20}{36} \times 100\\=56$ times

Therefore, number of times expected to loose

= 100-56

=44 times

8 0
3 years ago
which container hold the most? a. cylinder with a radius of 5 in and a height of 15 in b. sphere with a radius 6in c. come with
stepan [7]
Vcylinder=hpir^2 Vsphere=(4/3)pir^3 Vcone=(1/3)hpir^2 Vcylinder=15*pi*5^2=375pi in^3 Vsphere=(4/3)*pi*6^3=288pi in^3 Vcone=(1/3)*15*pi*8^2=320pi in^3 greatest is Vcylinder at 375pi in^3 answer is A (cylinder)
8 0
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A sphere of radius 3 is inscribed in a cylinder. What is the volume inside the cylinder but not inside the sphere?
Fed [463]

Answer:

18pi units³ or 56.5 units³ (3 sf)

Step-by-step explanation:

pi×r²×h - (4/3)(pi×r³)

r = 3 h = 2r = 6

pi(3²×6 - (4/3)(3³))

18pi units³

8 0
3 years ago
Select the correct answer.<br> Identify the axis of symmetry of the function graphed below.
Nady [450]

Answer:

D. x = -1.

Step-by-step explanation:

I have attached an explanation to your problem. Please see the attachment  below.

3 0
3 years ago
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