M=-1
4m+2(m+1)=9m +5
4m+2m+2=9m+5
6m+2=9m+5
6m+2-6m= 9m+5-6m
2-5=3m+5-5
-3/3=3m/3
m=-1
A) 5000 m²
b) A(x) = x(200 -2x)
c) 0 < x < 100
Step-by-step explanation:
b) The remaining fence, after the two sides of length x are fenced, is 200-2x. That is the length of the side parallel to the building. The product of the lengths parallel and perpendicular to the building is the area of the playground:
A(x) = x(200 -2x)
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a) A(50) = 50(200 -2·50) = 50·100 = 5000 . . . . m²
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c) The equation makes no sense if either length (x or 200-2x) is negative, so a reasonable domain is (0, 100). For x=0 or x=100, the playground area is zero, so we're not concerned with those cases, either. Those endpoints could be included in the domain if you like.
Answer:
all work for both worksheets are pictured and shown
Step-by-step explanation:
worksheet 2
28. 968/22=44
29. 27+8=35
30. 39×37=-1443
9514 1404 393
Answer:
28 square units
Step-by-step explanation:
The rectangle is 7-0 = 7 units high and 6-2 = 4 units wide. Its area is the product of these dimensions:
A = LW
A = (7)(4) = 28 . . . square units