The two data sets show random samples of the costs, in dollars, of cars purchased at two dealerships yesterday.

1 answer:

7 0

A) The mean of set 1 is 53,800, while the mean of set 2 is 38,600. The median of set 1 is 42,000, while the median of set 2 is 28,000.
B) The median is a more accurate estimate, because each set has 1 particularly large outlier which heavily skews the mean. In each set, the mean is actually higher than 4 out of the 5 data points, which is not very accurate in describing how much the typical car costs.

You might be interested in

If Carl, Steve and John have 40 sweets to share and John gets the most out of all three. What’s the smallest amount he can get?

Basile [38]

Answer:

13 +13 +14 ensures he is getting the smallest amount so its 14

Step-by-step explanation:

6 0

3 years ago

Use factoring to solve the quadratic equation x2 − 2x − 3 = 12.

melomori [17]

Answer:

$x_1=5\\x_2=-3$

Step-by-step explanation:

You have the following quadratic equation given in the problem:

$x^{2}-2x-3=12$

You must make the equation equal to zero, as following:

$x^{2}-2x-3-12=0$

Add like terms:

$x^{2}-2x-15=0$

Now, to factor the equation, you must find two numbers whose sum is -2 and whose product is -15. Therefore, you have:

$(x-5)(x+3)=0\\x_1=5\\x_2=-3$

7 0

3 years ago

Read 2 more answers

PLEASE HELPP I AM FAILING AND I NEED THIS ASAP!!! TYSM

Lana71 [14]

Answer:

See below for answers

Step-by-step explanation:

Do you mean $f(x)=2sin(x-1)$ or $f(x)=2sin(x) -1$ ?

Use the formula $f(x)=asin(bx+c)+d$ where $|a|$ is the amplitude, $-\frac{c}{b}$ is the phase shift, $d$ is the vertical shift, and the period is $\frac{2\pi}{|b|}$ .

Assuming your first case is true, the amplitude would be $|a|=|2|=2$ , your period is $\frac{2\pi}{|1|}=2\pi$ , and your midline/vertical shift is $d=0$ .