The point of intersection you are concerned with is the left-most of those of the graphed lines. Thus you want the two equatons that both have x-intercepts that are negative. Since the x-coefficient is positive in every case, this will mean the right-side constants of these equations both need to be negative. The appropriate choice is ...
A. 4x - 5y = -5 and 3x + 10y = -20
Answer:
dont you just subtract 90-61 to get 29 since a triangle is 90 degrees
758, you go by the one's number first. 5 and up rounds up to 10, so we goto the next number 50, 5 rounds up to 10, so up from 50 goes to the next hundred. 800 is the nearest hundred.
Answer:
y=12
Step-by-step explanation:
30,60,90 triangle
8*rad3=8rad3
8rad3/2=4rad3
4rad3*rad3=12
72.50 is rounded and the answer to this question