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tamaranim1 [39]
3 years ago
13

A part of 1500rs was lent on 10% p.A and the rest at 7% p.A. Simple interest. The total interest earned in 3 yrs was 396rs. What

was the sum lent at 10% p.A?
Mathematics
1 answer:
cricket20 [7]3 years ago
7 0

Answer:

  ₹900

Step-by-step explanation:

Let x represent the amount loaned at 10%. Then (1500-x) is the amount loaned at 7%, and the total interest for 3 years is ...

  i = Prt

  396 = x(0.10)(3) + (1500-x)(0.07)(3)

  396 = 0.09x +315 . . . . . simplify

  81 = 0.09x . . . . . . . . . . . subtract 315

  81/0.09 = x = 900 . . . . . divide by the coefficient of x

The sum lent at 10% was ₹900.

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A sine function has an amplitude of 3, a period of pi, and a phase shift of pi/2. What is the y-intercept of the function?
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Based on the calculations, we can logically deduce that the y-intercept of this sine function is equal to: A. 3.

<u>Given the following data:</u>

  • Amplitude = 3
  • Period = π
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<h3>How to determine the y-intercept of this function?</h3>

Mathematically, a sine function is modeled by this equation:

y = Asin(ωt + ø)

<u>Where:</u>

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  • t represents the period.
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Also, the period of a sine wave is given by:

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Substituting the given parameters into the equation, we have;

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At t = 0, we have:

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