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forsale [732]
3 years ago
10

PLEASEEEE HELPPPP ASAP(Essay Worth 10 points)

Mathematics
1 answer:
blagie [28]3 years ago
3 0

Answer:

its worth 5 no 10 :(

Step-by-step explanation:

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If m∠c=11x+85/3 and x=13 then what type of angle is c please help me with this
GuDViN [60]

Answer:

Acute angle

Step-by-step explanation:

Given that m<C = \frac{11x + 85}{3}, to find out the type of angle angle C is, evaluate the expression given by substituting x = 13, in the expression.

m<C = \frac{11x + 85}{3}

m<C = \frac{11(13) + 85}{3}

m<C = \frac{228}{3}

m<C = 76°

Acute angles are less than 90°.

m<C is less than 90°, therefore it is an acute angle.

5 0
3 years ago
The length of each side of a square is 6 feet more than the length of a side of a regular Octagon. The perimeter of the square i
goldfiish [28.3K]

9514 1404 393

Answer:

  • square: 12 ft sides
  • octagon: 6 ft sides

Step-by-step explanation:

This problem can be worked in your head.

If the perimeters of the square and regular octagon are the same, the side length of the 4-sided square must be the same as the length of 2 sides of the 8-sided octagon. Since the side of the square is 6 ft more than the side of the octagon, each side of the octagon must be 6 ft, and each side of the square must be 12 ft.

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We can let s represent the side length of the octagon. Then we have ...

  8s = perimeter of octagon

  4(s +6) = perimeter of square

These are equal, so ...

  4(s +6) = 8s

  s +6 = 2s . . . . . . divide by 4

  6 = s . . . . . . . . . . subtract s

The octagon has 6-ft sides; the square has 12-ft sides.

8 0
3 years ago
I WILL CROWN CORRECT ANSWER, PLS HELP ASAP5. Rewrite each of the following durations using sixteenth notes. Write in words and a
REY [17]

Answer:  

3/4

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1/2

When you make a fraction like this in words, all you have to do is Take the number put it on top and the worded number on the bottom. Unless directed otherwise.

5 0
3 years ago
A Geometric series has a first term of 4 and a common ratio of 6. what formula is equivalent to the partial sum of the first n t
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\bf \qquad \qquad \textit{sum of a finite geometric sequence}&#10;\\\\&#10;S_n=\sum\limits_{i=1}^{n}\ a_1\cdot r^{i-1}\implies S_n=a_1\left( \cfrac{1-r^n}{1-r} \right)\quad &#10;\begin{cases}&#10;n=n^{th}\ term\\&#10;a_1=\textit{first term's value}\\&#10;r=\textit{common ratio}\\&#10;----------\\&#10;a_1=4\\&#10;r=6&#10;\end{cases}&#10;\\\\\\&#10;S_n=4\left( \cfrac{1-6^n}{1-6} \right)\implies S_n=4\left( \cfrac{1-6^n}{-5} \right)
6 0
3 years ago
Which postulate (if any) should be used to show the triangles are congruent?
dezoksy [38]

Answer:

ASA

Step-by-step explanation:

SAS, it must go in order and SAS covers it up, Side, Angle, Side

7 0
2 years ago
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