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JulsSmile [24]
3 years ago
15

A + 2b = 12a + b = 8​

Mathematics
1 answer:
xxMikexx [17]3 years ago
4 0

Answer:

............................

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A tank contains 300 liters of fluid in which 40 grams of salt is dissolved. Brine containing 1 gram of salt per liter is then pu
bonufazy [111]

Answer:

A(t) = 300 -260e^(-t/50)

Step-by-step explanation:

The rate of change of A(t) is ...

A'(t) = 6 -6/300·A(t)

Rewriting, we have ...

A'(t) +(1/50)A(t) = 6

This has solution ...

A(t) = p + qe^-(t/50)

We need to find the values of p and q. Using the differential equation, we ahve ...

A'(t) = -q/50e^-(t/50) = 6 - (p +qe^-(t/50))/50

0 = 6 -p/50

p = 300

From the initial condition, ...

A(0) = 300 +q = 40

q = -260

So, the complete solution is ...

A(t) = 300 -260e^(-t/50)

___

The salt in the tank increases in exponentially decaying fashion from 40 grams to 300 grams with a time constant of 50 minutes.

6 0
3 years ago
Read 2 more answers
Give an example of an event in which all of the outcomes are not equally likely. Explain.
Kryger [21]
In order to do that we would need to see the list of potential answers. 
8 0
3 years ago
Maya deposits $8000 into an account that pays simple interest at a rate of 2% per year. How much interest will she be paid in th
Amiraneli [1.4K]
So just find 2% of 8000 and multiply by number of years since

I=PRT
R=rate
T=time in yyears
P=principle
I=interest

8000=principle
rate=2%
time in years=2

2%=0.02
so
I=8000 times 0.02 times 2
I=320

answe ris $320
7 0
3 years ago
Can someone help I don’t understand my answer are not adding up
andriy [413]

Answer:

B

Step-by-step explanation:

∠ ABC = 9x + 5 ( alternate angles )

∠ ABC and ∠ DCB are sam- side interior angles and sum to 180° , that is

9x + 5 + 16x = 180

25x + 5 = 180 ( subtract 5 from both sides )

25x = 175 ( divide both sides by 25 )

x = 7

Then

∠ ABC = 9x + 5 = 9(7) + 5 = 63 + 5 = 68° → B

6 0
3 years ago
Which expression is equivalent?
iVinArrow [24]

Answer:

\large\boxed{\dfrac{g^{15}}{8h^6}}

Step-by-step explanation:

\dfrac{\left(2g^5\right)^3}{\left(4h^2\right)^3}=\dfrac{\left(2g^5\right)^3}{\left(2^2h^2\right)^3}\qquad\text{use}\ (a^n)^m=a^{nm}\ \text{and}\ (ab)^n=a^nb^n\\\\=\dfrac{2^3g^{(5)(3)}}{2^{(2)(3)}h^{(2)(3)}}=\dfrac{2^3g^{15}}{2^6h^6}=\dfrac{2^3g^{15}}{2^{3+3}h^6}\qquad\text{use}\ a^n\cdot a^m=a^{n+m}\\\\=\dfrac{2^3g^{15}}{2^3\cdot2^3h^6}=\dfrac{g^{15}}{8h^6}

8 0
3 years ago
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