Answer:
A(t) = 300 -260e^(-t/50)
Step-by-step explanation:
The rate of change of A(t) is ...
A'(t) = 6 -6/300·A(t)
Rewriting, we have ...
A'(t) +(1/50)A(t) = 6
This has solution ...
A(t) = p + qe^-(t/50)
We need to find the values of p and q. Using the differential equation, we ahve ...
A'(t) = -q/50e^-(t/50) = 6 - (p +qe^-(t/50))/50
0 = 6 -p/50
p = 300
From the initial condition, ...
A(0) = 300 +q = 40
q = -260
So, the complete solution is ...
A(t) = 300 -260e^(-t/50)
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The salt in the tank increases in exponentially decaying fashion from 40 grams to 300 grams with a time constant of 50 minutes.
In order to do that we would need to see the list of potential answers.
So just find 2% of 8000 and multiply by number of years since
I=PRT
R=rate
T=time in yyears
P=principle
I=interest
8000=principle
rate=2%
time in years=2
2%=0.02
so
I=8000 times 0.02 times 2
I=320
answe ris $320
Answer:
B
Step-by-step explanation:
∠ ABC = 9x + 5 ( alternate angles )
∠ ABC and ∠ DCB are sam- side interior angles and sum to 180° , that is
9x + 5 + 16x = 180
25x + 5 = 180 ( subtract 5 from both sides )
25x = 175 ( divide both sides by 25 )
x = 7
Then
∠ ABC = 9x + 5 = 9(7) + 5 = 63 + 5 = 68° → B
Answer:
Step-by-step explanation:
