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den301095 [7]
3 years ago
8

What is the volume of a sphere having a diameter of 6 cm?

Mathematics
2 answers:
leonid [27]3 years ago
4 0

Answer:

113.1

Step-by-step explanation:

Volume of sphere = \frac{4}{3} × π × r²

Volume of sphere =  \frac{4}{3} × π × 3²

Volume of sphere =  \frac{4}{3} × π × 9

Volume of sphere =  \frac{4}{3} × 9 π

Volume of sphere = 113.1

Jlenok [28]3 years ago
3 0

Answer:

V=113.1cm^3

Step-by-step explanation:

The formula to calculate the volume of a sphere is:

V=\frac{4}{3}\pi r^3

Where r is the radius of the sphere.

In this case we do not know the radius of the sphere, but we know the diameter.

By definition the diameter of a sphere is equal to twice the radius. This is:

d = 2r

r = \frac{d}{2}

In this case d=6 cm

So

r = \frac{6}{2}

r = 3\ cm

Finally

V=\frac{4}{3}\pi 3^3

V=36\pi\ cm^3

V=113.1cm^3

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Answer:

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Step-by-step explanation:

<u>Concepts:</u>

Area of Square = s²

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Diagonals of the square are congruent and bisect each other, which forms a right angle with 90°

Segment addition postulate states that given 2 points A and C, a third point B lies on the line segment AC if and only if the distances between the points satisfy the equation AB + BC = AC.

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Question # 16

<em>Step One: Find the total area of two squares</em>

Large square: 5 × 5 = 25

Small square: 2 × 2 = 4

25 + 4 = 29

<em>Step Two: Find the area of the blank triangle</em>

b = 5 + 2 = 7

h = 2

A = bh / 2

A = (7) (2) / 2

A = 14 / 2

A = 7

<em>Step Three: Subtract the area of the blank triangle from the total area</em>

Total area = 29

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29 - 7 = 22

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Question # 17

<em>Step One: Find the length of PT</em>

Given:

  • PR = 4 cm
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PT = PR + RT [Segment addition postulate]

PT = (4) + (6)

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<em>Step Two: Find the length of S to PT perpendicularly</em>

According to the diagonal are perpendicular to each other and congruent. Therefore, the length of S to PT perpendicularly is half of the diagonal

Length of Diagonal = 4 cm

4 ÷ 2 = 2 cm

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Similar to step two, Q is the endpoint of one diagonal, and by definition, diagonals are perpendicular and congruent with each other. Therefore, the length of Q to PT perpendicularly is half of the diagonal.

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