Please help me with this! Very much appreciate
1 answer:
Answer:
The answers for your two problems, can be found below in the attached images.
Problem 1
Graph
The graph was plotted using a calculator. We can see that the graph opens up.
f(x) = x^2 + 4x +3
Vertex
The vertex is the minimum point of the equation
In this case Vertex (V) = (-2,-1)
Axis of symmetry
The x axis corresponding to the vertex component
x = -2
y intercept
Interception with the y-axis
From the first attached image, we can see that they y intercept occurs
at x = 0, y = 3
(0,3)
Problem 2
Graph.
The graph was plotted using a calculator. We can see that the graph opens up.
f(x) = 2x^2 + 3x +1
Vertex
The vertex is the minimum point of the equation
In this case Vertex (V) = (-0.75,-0.125)
Axis of symmetry
The x axis corresponding to the vertex component
x = -0.75
y intercept
Interception with the y-axis
From the second attached image, we can see that they y intercept occurs
at x = 0, y = 1
(0,1)
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from what I know
A=4
B=3
C=2
and a plus adds 0.33 and a minus minuses 0.33
question wants us to find yearly average or average per 1 year
since these grades span over 2 years, we must divide the total average by 2
averagefresh=sum of fresh grades/4 grades per year
averagesoph=sum of soph grades/4 grades per year
yearlyaverage=(averagefresh+averagesoph)/2
freshman:
(C)+(B)+(A)+(C-)=2+3+4+(2-0.33)=10.67
sophomore:
(B+)+(A-)+(C+)+(B-)=(3+0.33)+(4-0.33)+(2+0.33)+(3-0.33)=12
averagefresh=10.67/4=2.6675
averagesoph=12/4=3
yearlyaverage=(2.6675+3)/2=2.83375
so it's about a average