Answer:
Replicated chromosomes at metaphase I = 66
Sister chromatids at metaphase I = 66 x 2 = 132
Sister chromatids at prophase II = 66
Chromosomes in each sperm cells = 33
Explanation:
Metaphase I of meiosis I would have 66 replicated chromosomes in the testicular cells of the bird. Each of the replicated chromosomes would have two sister chromatids. So, a total of 66 replicated chromosomes would have 66 x 2 = 132 sister chromatids.
Due to segregation of homologous chromosomes towards opposite poles in anaphase I, each daughter cell formed by the end of meiosis I would have 33 replicated chromosomes. So, each of the daughter cells would have a total 33 x 2 = 66 sister chromatids at prophase II.
Since meiosis II maintains the chromosome number, each sperm cell formed by the end of meiosis II would have 33 chromosomes.
Answer:
A
Explanation:
Meiosis is the formation of non identical gametes
Answer:
Meiosis produces four genetically different haploid cells.
Gametic chromosomes have a different combination of alleles than parental chromosomes as a result of independent assortment
Explanation:
Meiosis and Mitosis are two types of cell division that occurs in living organisms. However, Mitosis produces daughter cells that are genetically identical to the parent cell while meiosis produces daughter cells that are genetically different from the parent cell. This accounts for the reason meiosis leads to genetic variation.
The production of genetically different cells by meiosis is as a result of the process of the random orientation of chromosomes during metaphase I of meiosis I. This process is called INDEPENDENT ASSORTMENT. However, crossing over occurs during prophase I of meiosis between non-sister chromatids of homologous chromosomes.
