I don't know any <em><u>slick</u></em> way to do this. I would just list the prime numbers
between 40 and 50 and test them one at a time.
The prime numbers between 40 and 50 are: 41, 43, 47
<u>Test 41:</u>
-- add 1 . . . 42
-- prime factors of 42 . . . 2, 3, 7
-- sum of the factors . . . 12
<u>Test 43:</u>
-- add 1 . . . 44
-- prime factors of 44 . . . 2, 11
-- sum of the factors . . . 13
<u>Test 47:</u>
-- add 1 . . . 48
-- prime factors of 48 . . . 2, 3,
-- sum of the factors . . . 5
Maybe I'm not understanding how to list prime factors, but so far,
I haven't found any number that answers the question.
Maybe if I write the prime factorization of 44 like this:
44 = 2 * 2 * 11
Now the items in the prime factorization do add up to 15.
So the answer would seem to be <em>43.</em>
In summary, you just multiply the percentage (move the decimal twice to the left) by the amount, which is 70 in this case.
0.47 x 70 = 32.9
Answer:
The 95% confidence interval for the true proportion would be given by (0.570;0.630)
.
And if we convert this into % we got (57.0%, 63.0%)
Step-by-step explanation:
The information given we have the following info given:
represent the sampel size
represent the sample proportion of interest
The confidence level is 95%, our significance level would be given by 
and 
. And the critical value would be given by:
The confidence interval for the mean is given by the following formula:
Replacing the info given we got:
The 95% confidence interval for the true proportion would be given by (0.570;0.630)
.
And if we convert this into % we got (57.0%, 63.0%)
X=12
-5+17=12 - this is the quickest way to solve an easy equation like this
