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love history [14]
3 years ago
14

Let x and s present the sample mean and sample standard deviation, respectively. Is it possible that around 70% of data lie with

in x-2s and x+2s? (Yes or no)
Mathematics
1 answer:
tensa zangetsu [6.8K]3 years ago
8 0

Using the Chebyshev's Theorem and the Empirical Rule, it is found that it is not possible that around 70% of data lie within x-2s and x+2s.

-------------------------

  • Distributions are classified as symmetric or not symmetric.
  • If the distribution is not symmetric, Chebyshev's Theorem is used, which states that <u>at least 75% of the measures are within 2 standard deviations of the mean</u>.
  • If the distribution is symmetric, the Empirical Rule is used, which states that <u>around 95% of the measures are within 2 standard deviations of the mean</u>.

Thus, from the above bullet points, at least 75% of the measures are within x-2s and x+2s, which means that the percentage of 70% is too small.

A similar problem is given at brainly.com/question/23612895

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Which expressions are equivalent? Select two answers.
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Answer:

<h2>A, C</h2>

Step-by-step explanation:

The distributive property:

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<em></em>

A.\\\\\dfrac{1}{5}(x-50)=\dfrac{1}{5}x-\left(\dfrac{1}{5}\right)(50)=\dfrac{1}{5}x-\dfrac{50}{5}=\dfrac{1}{5}x-10\\\\B.\\\\-\dfrac{1}{3}(3x+18)=\left(-\dfrac{1}{3}\right)(3x)+\left(-\dfrac{1}{3}\right)(18)=-\dfrac{3}{3}x-\dfrac{18}{3}=-x-6\\\\-x-6\neq\dfrac{1}{3}x-6

C.\\\\\dfrac{1}{2}(x+16)=\dfrac{1}{2}x+\left(\dfrac{1}{2}\right)(16)=\dfrac{1}{2}x+\dfrac{16}{2}=\dfrac{1}{2}x+8\\\\D.\\\\\dfrac{1}{8}(8x+8)=\left(\dfrac{1}{8}\right)(8x)+\left(\dfrac{1}{8}\right)(8)=\dfrac{8}{8}x+\dfrac{8}{8}=x+1\\\\x+1\neq\dfrac{1}{8}x+1\\\\E.\\\\-\dfrac{1}{4}(x+2)=-\dfrac{1}{4}x+\left(\dfrac{1}{4}\right)(2)=-\dfrac{1}{4}x+\dfrac{2\!\!\!\!\diagup^1}{4\!\!\!\!\!\diagup_2}=-\dfrac{1}{4}x+\dfrac{1}{2}\\\\-\dfrac{1}{4}x+\dfrac{1}{2}\neq-\dfrac{1}{4}x+2

4 0
3 years ago
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8 0
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Read 2 more answers
(1) 39 = 2x - 5(-3x + 16)
ella [17]

Answer:

The solution is x=7

Step-by-step explanation:

we have

39= 2x- 5(-3x+16)

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4 years ago
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