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3 years ago

Wich number is the principal square root of 49

1 answer:

3 0

A principle square root of a real number that's not negative, such as 49, is the square root of that number that is not negative.

If you take the square root of 49, you get either -7 or 7, since both $7^{2}$ and $(-7)^{2}$ equal 49. However, the principle square root would be A) 7, since it's not negative.

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eric can spend a maximum of $270 on office supplies. Each rem of paper costs $6. Each ink catridge costs $18. Which of the follo

Vladimir [108]

If we say A = ream of paper and B = cost of ink than we can set-up an expression to calculate when A is equal to a number what the number of B will be. Maximim of 270$ so anything we buy must be equal to this. Ream of paper cost 6$ each so 6A represents the number of reams bought since we said A is number of reams of paper. Ink Cartridges are 18$ each so 18B would represent this based on B = to cost of ink. Now setting up our equation 6A + 18B = 270 When A = 1 B = 14.67 Ink Cartridges When A = 1 Ream ofpaper

7 0

3 years ago

Latoya's annual salary is $26,000. A total of $7352.24 will be deducted for taxes and health insurance. She will receive her pay

Anna71 [15]

Step-by-step explanation:

Lets translate this word problem into math.

"Latoya's annual salary is $26,000" = We start with the number 26,000

"A total of $7352.24 will be deducted for taxes and health insurance" = It's the number we started with "deducted" (minus) 7352.24

"She will receive her paycheck monthly in 12 equal installments" = Our number will be divided by 12

"How much will she get paid with each paycheck?" = "Find answer pls thx"

To put it all together...

$\frac{26,000-7,352.24}{12}$

Now all we have to do is solve!

$\frac{26,000-7,352.24}{12}$

Subtract.

$\frac{18,647.76}{12}$

Divide.

$1,553.98$

Answer:

Latoya will get paid $1,553.98 with each paycheck.

7 0

2 years ago

PLEASE I BEG OF YOU HELP ME

earnstyle [38]

It is 90 I believe please tell me if I was wrong

4 0

2 years ago

Match the expressions with their equivalent simplified expressions.

Tasya [4]

Answer:

$\sqrt[4]{\frac{16x^6y^4}{81x^2y^8}}\rightarrow\frac{2x}{3y}\\\sqrt[4]{\frac{81x^2y^{10}}{81x^6y^6}} \rightarrow\frac{3y}{2x}\\\sqrt[3]{\frac{64x^8y^7}{125x^2y^{10}}}\rightarrow\frac{4x^2}{5y}\\\sqrt[5]{\frac{243x^{17}y^{16}}{32x^7y^{21}}}\rightarrow\frac{3x^2}{2y}\\\sqrt[5]{\frac{32x^{12}y^{15}}{243x^7y^{10}}} \rightarrow\frac{2xy}{3}\\\sqrt[4]{\frac{16x^{10}y^{9}}{256x^2y^{17}}}\rightarrow\frac{x}{2y}$

Step-by-step explanation:

$\sqrt[4]{\frac{16x^6y^4}{81x^2y^8}} =\sqrt[4]{\frac{(2^4)(x^{6-2})(y^{4-8})}{(3^4)}} =\sqrt[4]{\frac{2^4x^4y^{-4}}{3^4}} =\frac{2xy^{-1}}{3}=\frac{2x}{3y}$

$\sqrt[4]{\frac{81x^2y^{10}}{81x^6y^6}} =\sqrt[4]{\frac{(3^4)(x^{2-6})(y^{10-6})}{(2^4)}} =\sqrt[4]{\frac{3^4x^{-4}y^{4}}{2^4}} =\frac{3x^{-1}y^1}{3}=\frac{3y}{2x}$

$\sqrt[3]{\frac{64x^8y^7}{125x^2y^{10}}} =\sqrt[3]{\frac{(4^3)(x^{8-2})(y^{7-10})}{(5^3)}} =\sqrt[3]{\frac{4^3x^6y^{-3}}{5^3}} =\frac{4x^2y^{-1}}{5}=\frac{4x^2}{5y}$

$\sqrt[5]{\frac{243x^{17}y^{16}}{32x^7y^{21}}} =\sqrt[5]{\frac{(3^5)(x^{17-7})(y^{16-21})}{(2^5)}} =\sqrt[5]{\frac{3^5x^{10}y^{-5}}{2^5}} =\frac{3x^2y^{-1}}{2}=\frac{3x^2}{2y}$

$\sqrt[5]{\frac{32x^{12}y^{15}}{243x^7y^{10}}} =\sqrt[5]{\frac{(2^5)(x^{12-7})(y^{15-10})}{(3^5)}} =\sqrt[5]{\frac{2^5x^{5}y^{5}}{3^5}} =\frac{2x^1y^{1}}{3}=\frac{2xy}{3}$

$\sqrt[4]{\frac{16x^{10}y^{9}}{256x^2y^{17}}} =\sqrt[4]{\frac{(2^4)(x^{10-2})(y^{9-17})}{(4^4)}} =\sqrt[4]{\frac{2^4x^{8}y^{-8}}{4^4}} =\frac{2x^{1}y^{-1}}{4}=\frac{x}{2y}$