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3 years ago

How to solve inequaities?

1 answer:

8 0

Many simple inequalities can be solved by adding, subtracting, multiplying or dividing both sides until you are left with the variable on its own.
But these things will change direction of the inequality:
Don't multiply or divide by a variable (unless you know it is always positive or always negative)

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(10) Jasmine uses 14.24 pounds of fruit for

solniwko [45]

The answer is 0.89 pounds of fruit per serving- please give brainliest answer!

5 0

3 years ago

What is the best estimate for the sum of 3/4 and 1/12

TEA [102]

Well first you would find a common denominator which would be 1w and then since you multiplied 4 by 3 to get to 12 you multiply 3 by 3 which is 9. So then you would have 9/12 + 1/12 which = 10/12

3 0

2 years ago

A standardized test was given to a set of high school juniors and the distribution of the data is bell shaped. The mean score is

stira [4]

Answer:

920 points.

Step-by-step explanation:

We have been given that the mean score for a standardized test is 800 and the standard deviation is 120. To qualify for a special summer camp for accelerated students, a student must score within the top 16% of all scores on the test.

First of all we will find probability of 0.16 using normal distribution table.

Using normal distribution our Z score will be 0.994458

Now we will use raw-score formula to find the score (x) that a student must make to qualify for summer camp.

$x=\text{Mean}+\text{ Standard deviation* Z score}$

Upon substituting our given values in above formula we will get,

$x=800+120\times 0.994458$

$x=800+119.33496$

$x=919.33496$

Upon rounding to nearest whole number we will get,

$x=920$

Therefore, a student must make 920 points to qualify for summer camp.

5 0

3 years ago

To prove :One plus cot square theta into tan theta by sec square theta = cot theta

pickupchik [31]

we are given

$\frac{(1+cot^2(\theta))*tan(\theta)}{sec^2(\theta)} =cot(\theta)$

We will simplify left side and make it equal to right side

Left side:

$\frac{(1+cot^2(\theta))*tan(\theta)}{sec^2(\theta)}$

we can use trigonometric identity

$1+cot^2(\theta)=csc^2(\theta)$

we can replace it

$\frac{(csc^2(\theta))*tan(\theta)}{sec^2(\theta)}$

we know that

csc=1/sin and sec=1/cos

so, we can replace it

and we get

$\frac{cos^2(\theta)tan(\theta)}{sin^2(\theta)}$

now, we know that

tan =sin/cos

$\frac{cos^2(\theta)*sin(\theta)}{sin^2(\theta)*cos(\theta)}$

we can simplify it

and we get

$\frac{cos(\theta)}{sin(\theta)}$

we can also write it as

$=cot(\theta)$

Right Side:

$cot(\theta)$

we can see that

left side = right side

so,

$\frac{(1+cot^2(\theta))*tan(\theta)}{sec^2(\theta)} =cot(\theta)$ ......Answer

6 0

3 years ago

Suppose you buy a CD for $300 that earns 3% APR and is compounded quarterly. The CD matures in 5 years. Assume that if funds are

klio [65]

Value of the CD after 3 months is given by 300(1 + 0.03 / 4) = 300(1 + 0.0075) = 300 x 1.0075 = $302.25.
Therefore, interest for 3 months = $302.25 - $300 = $2.25

4 0

3 years ago