To find out if a dye is a mixture or not, you can make use of the chromatography method of separation.
If the dye is a mixture, the different elements inside the mixture will be separated out during chromatography and they will form different bands on the cinematographic paper but if the dye is composed of only one element, only one band will be formed on the cinematographic paper.
Before you begin titration, drops of indicator are added to the Erlenmeyer flask. This happens when preparing to measure pH change.
Answer:
ATP
Explanation :
Because the energy is released during the process of glycolysis in cellular respiration and then the molecule is captured by the energy carrying molecule which is the ATP (adenosine triphosphate).
The mass percentage composition of nitrogen in CO(NH2)2 is 46 .7%
calculation
% mass = molar mass of nitrogen/ molar mass of Co(NH2)2
molar mass of nitrogen = 14 x2 = 28g/mol since there is two nitrogen atom in Co(NH2)2\
molar mass of CO(NH2)2 = 12 + 16 + (14 x2) +( 2 x2)= 60 g/mol
the % mass is therefore =28 / 60 x100 =46.7%
Explanation:
a)
![k _{sp} = [Ag {}^{ + } ][Cl {}^{ - } ] \\ but \: [Ag {}^{ + } ] = [Cl {}^{ - } ] \\ k _{sp} = [Ag {}^{ + } ] {}^{2} \\ [Ag {}^{ + } ] = \sqrt{k _{sp}} \\ = \sqrt{1.8 \times {10}^{ - 10} } \\ = 1.34 \times {10}^{ - 5} mol {dm}^{ - 3}](https://tex.z-dn.net/?f=k%20_%7Bsp%7D%20%3D%20%5BAg%20%7B%7D%5E%7B%20%2B%20%7D%20%5D%5BCl%20%7B%7D%5E%7B%20-%20%7D%20%5D%20%5C%5C%20but%20%5C%3A%20%5BAg%20%7B%7D%5E%7B%20%2B%20%7D%20%5D%20%3D%20%5BCl%20%7B%7D%5E%7B%20-%20%7D%20%5D%20%5C%5C%20k%20_%7Bsp%7D%20%3D%20%5BAg%20%7B%7D%5E%7B%20%2B%20%7D%20%5D%20%7B%7D%5E%7B2%7D%20%20%5C%5C%20%5BAg%20%7B%7D%5E%7B%20%2B%20%7D%20%5D%20%3D%20%20%5Csqrt%7Bk%20_%7Bsp%7D%7D%20%20%5C%5C%20%20%3D%20%20%5Csqrt%7B1.8%20%5Ctimes%20%20%7B10%7D%5E%7B%20-%2010%7D%20%7D%20%20%5C%5C%20%20%3D%201.34%20%5Ctimes%20%20%7B10%7D%5E%7B%20-%205%7D%20mol%20%7Bdm%7D%5E%7B%20-%203%7D%20)
b)
It has not reached equilibrium because the silver concentration is not yet equal to the value of Ksp.
c)
Yes it will dissolve in order to establish the equilibrium.
