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Svetach [21]
3 years ago
5

How many joules of heat are needed to raise the temperature of 10.0 g of aluminum from 22°C to 55°C, if the specific heat of alu

minum is 0.90 J/g° C?
Chemistry
1 answer:
Sergio039 [100]3 years ago
5 0

Answer:

297

Explanation:

55-22=33

Then use 33 *10*0.9

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What are the units of k in the following expression: rate = k [A][B]?
Aleks04 [339]
The answer is B since it's a second order reaction.
8 0
3 years ago
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A chemist pours 1 mol of zinc granules into one beaker and 1 mol of zinc chloride powder into another beaker. What do the two sa
Oksana_A [137]
Answer is: <span> two samples have in common same amount of substance and same number of particles.
1) There are same amount of substance in both beakers:
n(Zn) = 1 mol.
n(ZnCl</span>₂) = 1 mol.
2) There are same number of particles (atoms, molecules, ions) in both beakers:
N(Zn) = n(Zn) · Na.
N(Zn) = 1 mol · 6.023·10²³ 1/mol = 6.023·10²³ atoms of zinc.
N(ZnCl₂) = n(ZnCl₂) · Na.
N(ZnCl₂) = 1 mol · 6.023·10²³ 1/mol = 6.023·10²³ molecules of zinc(II) chloride.
Na - Avogadro number.


5 0
3 years ago
Read 2 more answers
The wavelength of the blue light given off by a mercury vapor street lamp is 457 nm. What is the frequency of this light in hert
Fed [463]

Answer:

6.56×10¹⁴ Hz

Explanation:

From the question given above, the following data were obtained:

Wavelength = 457 nm

Frequency =?

Next, we shall convert 457 nm to metre (m). This can be obtained as follow:

1 nm = 1×10¯⁹ m

Therefore,

457 nm = 457 nm × 1×10¯⁹ m / 1 nm

457 nm = 4.57×10¯⁷ m

Thus, 457 nm is equivalent to 4.57×10¯⁷ m

Finally, we shall determine the frequency of the blue light as follow:

Wavelength = 4.57×10¯⁷ m

Velocity of light = 3×10⁸ m/s

Frequency =?

Velocity = wavelength x frequency

3×10⁸ = 4.57×10¯⁷ × frequency

Divide both side by 4.57×10¯⁷

frequency = 3×10⁸ / 4.57×10¯⁷

frequency = 6.56×10¹⁴ Hz

Therefore, the frequency of the blue light is 6.56×10¹⁴ Hz

6 0
3 years ago
The equilibrium constant kp at 427°c for the reaction n 2( g) 3h 2( g) 2nh 3( g) is 9. 4 × 10 –5. what is δ g° for the reaction
SashulF [63]

ΔG° for the reaction is 5.47kJ mol⁻¹.

The energy that a substance has available for utilization in a chemical reaction or transformation is known as the Gibbs free energy. Things frequently change into other things that have less Gibbs free energy. The Gibbs free energy change indicates whether a chemical reaction will take place spontaneously or not.

By using the formula;

ΔG° = −RTlnKp

Where,

R = 8.3Jk⁻¹mol⁻¹

T = Temperature = 427 + 273 = 700 K

Kp = 8×10⁻⁵(given)

Substituting the value, we get,

ΔG° = −8.3 × 700 × ln(23×10⁻⁵)

ΔG° = −8.3 × 700 × (ln(2³)+ln 10⁻⁵)

       =  - 8.3 × 700 × (ln(2³)+ln 10⁻⁵)

       = − 8.3 × 700 × (2.07−11.5)

       =5.47×10⁴Jmol¹

       =5.47kJ mol⁻¹

Therefore,  ΔG° for the reaction is 5.47kJ mol⁻¹.

Learn more about Gibbs free energy here:

brainly.com/question/13765848

#SPJ4

7 0
2 years ago
How many atoms are in 6.2 moles of aluminum
daser333 [38]
I think that, considering that a mole contains an Avogadro's number of elements, there should be 6.2× an Avogadro's Number of atoms of Al. 6.2×6.022×1023=3.733×10<span>24 atoms</span>
8 0
4 years ago
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