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Nina [5.8K]
4 years ago
15

Add the following fractions. 3/8 + 5/12 = a 8/20 b 19/24 c 8/24 d 1/3

Mathematics
2 answers:
loris [4]4 years ago
8 0
3/8 + 5/12 = 

B. 19/24
Goshia [24]4 years ago
5 0
We can calculate the mmc between 8 and 12

8, 12 | 2

4 , 6 | 2

2 , 3 | 2

1 , 3 | 3

1, 1 | 1

mmc = 2 × 2× 2×3

mmc = 24

24 ÷ 8 = 3

And

24 ÷ 12 = 2

3/8 + 5/12 = ( 3× 3+ 5×2)/24

= (9 + 10)/24

= 19 / 24

Answer = 19/24

Another way of calculating would be to multiply the denominator and multiply the extremes.


3/8 + 5/12 = ( 3 × 12 + 8×5)/8×12

= ( 36 + 40)/96

= 76/96

Division by 2

= 38 / 48

Division by 2

= 19 / 24

I hope this has helped.
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Answer:

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Lillian's graduation picnic will cost $20 if it has 4 attendees. At most how many attendees can
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3 years ago
Abby, Deborah, Mei-Ling, Sam, and Roberto work in a firm's public relations office. Their employer must choose two of them to at
sattari [20]

Answer:

a) Ω = { {Abby, Deborath}, {Abby, Mei-Ling}, {Abby, Sam}, {Abby,Roberto}, {Deborah, Mei-Ling}, {Deborah, Sam}, {Deborah, Roberto}, {Mei-Ling, Sam}, {Mei-Ling, Roberto}, {Sam, Roberto} }

b) 0.1

c) 0.4

d) 0.3

Step-by-step explanation:

a) The sample space must contain every possible combination of two names. Since we dont care about the <em>order</em> of the chosen names, we can describe every element of the sample space as a <em>subset</em> of 2 elements of the set {Abby, Deborah, Mei-Ling, Sam, Roberto}. That subset will represent the names of the chosen persons. With this in mind, we conclude that the sample space is

Ω = { {Abby, Deborath}, {Abby, Mei-Ling}, {Abby, Sam}, {Abby,Roberto}, {Deborah, Mei-Ling}, {Deborah, Sam}, {Deborah, Roberto}, {Mei-Ling, Sam}, {Mei-Ling, Roberto}, {Sam, Roberto} }

b) The cardinality of the sample space Ω is 10. Since all choices are <em>equally likely</em>, any choice will have probability \frac{1}{10} = 0.1 , because the 10 of them combined must add up 1.

c) We need to find all possible choices that includes Mei-Ling, those will be our <em>favourable cases. </em>The amount of favourable cases must be divided to the total amount of cases (the cardinality of Ω) in order to obtain the probability of Mei-Ling being chosen. Mei-Ling is included on 4 choices (one for each of her partners), this means that she has a probability of \frac{4}{10} = 0.4  to being chosen.

d) We have <em>3 favourable cases </em>,the choices {Abby, Deborah}, {Abby, Mei-Ling} and {Deborah, Mei-Ling}, which neither of them contain a man. By dividing that number to the total number of cases, we obtain a probability of \frac{3}{10} = 0.3  that neither of the two men are chosen

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4 years ago
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olga55 [171]
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shutvik [7]

Answer

t=19

Step-by-step explanation:

12+7= 19

19 -7 =12

U 2 can help me by marking as brainliest........

8 0
3 years ago
Read 2 more answers
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