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Naya [18.7K]
4 years ago
9

If a figure has been dilated by a scale factor of 1/3 which transformation could be used to prove the figures are similar using

the AA similarity postulate?
Mathematics
2 answers:
tamaranim1 [39]4 years ago
6 0

Answer:

A translation because it can map one angle onto another since dilations preserve angle measures of triangles.

Step-by-step explanation:

I took the test and got the answer right

Vlad [161]4 years ago
5 0

Answer:

A translation because it can map one angle onto another since dilation preserve angle measures of triangles.

Step-by-step explanation:

In order to prove the two triangles by AA postulate, we must meet the conditions of the AA similarity postulate that says-

"Two triangles that have two congruent angles are similar".

So, we have to prove at least two corresponding angles of the given two triangles congruent.

One triangle is the dilation of the other. When we dilate a figure, the things that change are:

1. Lengths - Dilation changes the lengths of each side of the figure.

2. Size - Dilation changes the size of the figure.

When we dilate a figure, the things that do not change are:

1. Orientation - Dilation preserve orientation

2. Angles - Dilation preserves the interior angles of the figure.

So, the transformation that will preserve both orientation and angles will be used to prove triangles similarity using AA postulate.

A translation because it can map one angle onto another since dilation preserve angle measures of triangles.

A translation only moves the entire figure and thus we can overlap the vertices of the triangle and find whether the angles are congruent or not.

With the translation we will prove that other pair of angles of the triangles are congruent and thus the two triangles can be proved similar using the AA similarity postulate.

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I think it’s either 8 or negative 8
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A2-b2 ÷5a-5b factorise​
katrin2010 [14]

Answer:

Reformatting the input :

Changes made to your input should not affect the solution:

(1): "b2"   was replaced by   "b^2".  1 more similar replacement(s).

STEP

1

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           5a + 5b

Simplify   ———————

           a2 - b2

STEP

2

:

Pulling out like terms

2.1     Pull out like factors :

  5a + 5b  =   5 • (a + b)  

Trying to factor as a Difference of Squares:

2.2      Factoring:  a2 - b2  

Theory : A difference of two perfect squares,  A2 - B2  can be factored into  (A+B) • (A-B)

Proof :  (A+B) • (A-B) =

        A2 - AB + BA - B2 =

        A2 - AB + AB - B2 =

        A2 - B2

Note :  AB = BA is the commutative property of multiplication.

Note :  - AB + AB equals zero and is therefore eliminated from the expression.

Check :  a2  is the square of  a1  

Check :  b2  is the square of  b1  

Factorization is :       (a + b)  •  (a - b)  

Canceling Out :

2.3    Cancel out  (a + b)  which appears on both sides of the fraction line.

Final result :

   5 / a -b  

 

 

Step-by-step explanation:

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3 years ago
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Alexeev081 [22]

Answer:

<u>a) x = 3</u>

<u>b) z = 10</u>

<u>c) p = 2</u>

<u>d) x = 7</u>

<u>e) u = 1</u>

Step-by-step explanation:

a) 2x = 6

Despejamos x dividiendo por 2 a amabos lados de la eacuacion.

(2/2)x = 6/2

<u>x = 3</u>

Si remplazamos x en la ecuación original:

2(3)=6

6 = 6

Queda demostrado.

b) 10 + z = 20

Despejamos z restando 10 en amabos lados de la eacuacion.

10-10+z = 20-10

<u>z = 10</u>

Si remplazamos z en la ecuación original:

10 + 10=20

20 = 20

Queda demostrado.

c) p + 9 = 11

Despejamos p restando 9 en amabos lados de la eacuacion.

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<u>p = 2</u>

Si remplazamos p en la ecuación original:

2 + 9 = 11

11 = 11

Queda demostrado.

d) 3x + 8 = 29

Despejamos x restando 8 en amabos lados de la eacuacion y luego divideindo por 3 en ambos lados de la ecuación.

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(3/3)x = 21/3

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Si remplazamos x en la ecuación original:

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29 = 29

Queda demostrado

e) 2u + 8 = 10

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(2/2)x = 2/2

<u>x = 1</u>

Si remplazamos x en la ecuación original:

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2 + 8 = 10

10 = 10

Queda demostrado

Espero te haya sido de ayuda!

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Answer: 29

Step-by-step explanation:

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= 35-15-1

= 19

According to the question,

Number of people in front of Amy + Number of people behind Jed =24

⇒ 19 +  Number of people behind Jed =24

⇒  Number of people behind Jed =24 -19 = 5

Then, Number of people are in front of Jed = 35 - (Jed and people behind Jed)

= 35-(5+1)

= 35-6=29

Hence, there are 29 people are in front of Jed.

7 0
3 years ago
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