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3 years ago

What is 46 percent of 22

1 answer:

3 0

A percentage describes how many parts there are out of one hundred parts of a particular thing. It is often denoted with the percentage sign “%”. To get the 46 percent of 22, we need to multiply 22 to .46 that would equal to 10.12. Hence, the 46 percent of 22 is 10.12.

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If we did not write the equation 5x=21, instead we wrote it 21=5x,

elixir [45]

True we would get a different solution

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3 years ago

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The m∠ACD = (4x + 4)° and m∠ABD = (6x - 14)°. Find m∠ACD.

Greeley [361]

X=9, so m∠ACD= 40...

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3 years ago

12*10^5 or 1.2*10^6 which one is closer to 1 million? please explain.

Salsk061 [2.6K]

12*10^5 = 12*100000 = 1200000 ;
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3 years ago

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There are two precalculus sections at a high school. Mr. Abel's class has 10 girls and 6 boys, while Mr. Bonitz's class has 1

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3 years ago

Mathematical Statistics with Applications Homework Help

photoshop1234 [79]

7.37:

a. W follows a chi-squared distribution with 5 degrees of freedom. See theorem 7.2 from the same chapter, which says

$\displaystyle \sum_{i=1}^n\left(\frac{Y_i-\mu}{\sigma}\right)^2$

is chi-squared distributed with n d.f.. Here we have $\mu=0$ and $\sigma=1$ .

b. U follows a chi-squared distribution with 4 degrees of freedom. See theorem 7.3:

$\displaystyle \frac1{\sigma^2}\sum_{i=1}^n (Y_i-\overline Y)^2$

is chi-squared distributed with n - 1 d.f..

c. Y₆² is chi-square distributed for the same reason as W, but with d.f. = 1. The sum of chi-squared distributed random variables is itself chi-squared distributed, with d.f. equal to the sum of the individual random variables' d.f.s. Then U + Y₆² is chi-squared distributed with 5 + 1 = 6 degrees of freedom.

7.38:

a. Notice that

$\dfrac{\sqrt 5 Y_6}{\sqrt W} = \dfrac{Y_6}{\sqrt{\frac W5}}$

and see definition 7.2 for the t distribution. Since Y₆ is normally distributed with mean 0 and s.d. 1, it follows that this random variable is t distributed with 5 degrees of freedom.

b. Similar manipulation gives

$\dfrac{2Y_6}{\sqrt U} = \dfrac{\sqrt4 Y_6}{\sqrt U} = \dfrac{Y_6}{\sqrt{\frac U4}}$

so this r.v. is t distributed with 4 degrees of freedom.

4 0

3 years ago