The width of a rectangle is 2 cm less than its length. The perimeter is 52 cm. The length is:
1 answer:
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Answer is 10.2 + 3.1x
Solve by combining like terms
Solve by combining like terms
Since the area of a square is equal to the square of one of its side's length, then the area should be equivalent to 
.
---> equation (1)
By using pythagoras rule which states that the
---> equation (2)
where the opposite side's length is 8 and the hypotenuse side's length is 10
by substituting by the values in equation (2) therefore,
substitute this value in equation (1) then
where A is the area of the square whose side is x
By using pythagoras rule which states that the
where the opposite side's length is 8 and the hypotenuse side's length is 10
by substituting by the values in equation (2) therefore,
where A is the area of the square whose side is x