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ahrayia [7]
3 years ago
13

The radius of circle L is 22 cm. What is the length of its diameter?

Mathematics
1 answer:
xeze [42]3 years ago
6 0
Diameter = Radius * 2
Radius = Diameter/2

22 = Diameter/2

Multiply both sides by 2

22 * 2 = Diameter

Diameter = 44 cm
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vekshin1

Answer:

(a) l = -w + 21

(b) Domain: 0 <em>(See attachment for graph)</em>

(c) f(w) = -w + 21

Step-by-step explanation:

Given

2(l + w) = 42

l = length

w = width

Solving (a): A function; l in terms of w

All we need to do is make l the subject in 2(l + w) = 42

Divide through by 2

l + w = 21

Subtract w from both sides

l + w - w = 21 - w

l  = 21 - w

Reorder

l = -w + 21

Solving (b): The graph

In (a), we have:

l = -w + 21

Since l and w are the dimensions of the fence, they can't be less than 1

So, the domain of the function can be 0

--------------------------------------------------------------------------------------------------

To check this

When w = 1

l = -1 + 21

l = 20

(w,l) = (1,20)

When w = 20

l = -20 + 21

l = 1

(w,l)= (20,1)

--------------------------------------------------------------------------------------------------

<em>See attachment for graph</em>

<em></em>

Solving (c): Write l as a function f(w)

In (a), we have:

l = -w + 21

Writing l as a function, we have:

l = f(w)

Substitute f(w) for l in l = -w + 21

l = -w + 21 becomes

f(w) = -w + 21

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What is the value of x in a 45-45-90 triangle and the hypotenuse is 4?
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Answer:

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Step-by-step explanation:

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  x = 4/√2 = 4(√2)/2

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