2x+y>-4, 2*5-12=10-12= - 2, -2 > -4 (5, -12) matched, 2*0 + 1= 1> - 4, (0,1) matched, 2*-1 + (-1) = -3 > -4, (-1,-1) matched, the solutions are (5, -12) , (0,1) and (-1,-1), if the question is 2x+y>-4,
24q^2 / 8q^-3
lets break this down...
24/8 = 3
q^2 / q^-3....when dividing exponents with the same base, keep the base and subtract the exponents. q^2 / q^-3 = q^(2 -(-3) = q^(2 + 3) = q^5
put them together and u get : 3q^5
Answer:
Step-by-step explanation:
1 Simplify 19-7 to 12.
12^2−8×3+4×3−5
2 Simplify 12^2 to 144
144−8×3+4×3−5
3 Simplify 8×3 to 24.
144−24+4×3−5
4 Simplify 4×3 to 12.
144−24+12−5
5 Simplify 144-24 to 120.
120+12-5
6 Simplify 120+12 to 132.
132-5
7 Simplify.
127
Answer:
y+11=-
(x-4)
Step-by-step explanation:
since the equation is perpendicular to y=4x-2, m=-1/4 (negative reciprocal). (x_1,y_1)=(4,-11), plug all the values into the equation y- y_1 = m(x-x_1) and we get y+11=-(x-4)
Answer:
Step-by-step explanation:
Multiply and divide by the conjugate.
The conjugate is the denominator with the sign of the complex number the opposite of the denominator.
Quotient =
