Calculate the energy of the orange light emitted, per photon, by a neon sign with a frequency of 4.89 × 1014 hz.
2 answers:
The energy if of a photon is (Planck's Konstant) x (frequency).
Planck's Konstant is 6.62607004 × 10⁻³⁴ m²-kg/s .
So the photon's energy is
(6.626 × 10⁻³⁴ m²-kg/s) x (4.89 x 10¹⁴ / sec)
= (32.4 x 10⁻²⁰) m²-kg/s²
= 3.24 x 10⁻¹⁹ joule
3.24 x 10⁻¹⁹ Joule
<h3>
Further explanation</h3>
<u>Given:</u>
A neon sign with a frequency of 4.89 x 10¹⁴ Hz.
<u>Question:</u>
The energy of the orange light emitted per photon (in joules).
<u>The Process:</u>
The energy of a photon is given by
- E = energy in joules
- h = Planck's constant 6.63 x 10⁻³⁴ Js
- f = frequency of light in Hz (sometimes the symbol f is written as v)
Let us find out the energy of the orange light emitted per photon.
Thus, we get a result of
- - - - - - - - - -
Notes:
- When an electron moves between energy levels it must emit or absorb energy.
- The energy emitted or absorbed corresponds to the difference between the two allowed energy states, i.e., as packets of light called photons.
- A higher energy photon corresponds to a higher frequency (shorter wavelength) of light.
<h3>Learn more</h3>
- What is the charge on 1.0 kg of protons? brainly.com/question/9425838#
- Determine the density of our sun at the end of its lifetime brainly.com/question/5189537
- Find out the kinetic energy of the emitted electrons when metal is exposed to UV rays brainly.com/question/5416146
Keywords: calculate, the energy of the orange light emitted, per photon, by a neon sign, frequency, Planck's constant
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