Answer:
q' = 0.5q
Hence, the charge stored is also halved
Explanation:
The capacitance of a capacitor is given by the following formula:
------- eqn(1)
where,
C = Capacitance of the capacitor
q = charge stored in the capacitor
V = potential across the capacitor
Now, if we make potential half of its initial value:
<u></u>
<u>q' = 0.5q </u>
<u>Hence, the charge stored is also halved </u>
I'm not sure if a figure or some choices go along with this, but the closer to the sea floor the diver is, the lower the potential energy
C.0 because it didn't move<span />
X=mass × velocity
x=25×4
=100kgm/s
You can use the impulse momentum theorem and just subtract the two momenta.
P1 - P2 = (16-1.2)(11.5e4)=1702000Ns
If you first worked out the force and integrated it over time the result is the same
