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sergij07 [2.7K]
3 years ago
13

true or false, figures that are the exact same shape but not the same size are called congruent figures

Mathematics
1 answer:
svlad2 [7]3 years ago
7 0
False congruent figures mean the run equal
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I WILL GIVE BRAINILEST!!! Elvira is interested in collecting data about how many students use each of the tables during each lun
Anarel [89]

Answer:

yes

Step-by-step explanation:

2 plus 2 is 4

5 0
3 years ago
RS = 4x – 9, ST = 19, RT = 80 – 14<br><br> Equation:<br><br> 82 – 14<br><br> RS<br><br> RT
algol13

Step-by-step explanation:

The expressions are not properly written

Given

RS = 4x – 9

ST = 19

RT = 8x – 14

Based on the given parameters, the addition postulate below is true

RS+ST = RT

Substitute

4x-9+19 = 8x-14

collect like terms

4x-8x = -14-19+9

-4x = -33+9

-4x = -24

x = -24/-4

x = 6

Get RS:

RS = 4x-9

RS = 4(6)- 9

RS = 24-9

RS = 15

Get RT:

RT = 8x - 14

RT = 8(6)-14

RT = 48-14

RT = 34

4 0
3 years ago
87 less than the quotient of an unknown number and 43 is -75
choli [55]
The statement is expressed algebraically as
(x/43) - 87 = -75
8 0
3 years ago
Simplify. Rewrite the expression in the form 5^n<br>(5^3)^2=<br>​
Temka [501]

Answer:

5^12

Step-by-step explanation:

index notation rules states that when there is a power inside AND outside the brackets, they shall multiply together. hence, we will multiply 3 and 2 so we will get 6 and thus the answer will be 5^6. Sike, that's not the answer, we forgot to multiply 5 with that power too... so we will get 25^6 because same power (outside brackey) will affect everything inside...

now after we got 25^6, we need to simplify it to get 5^n ....

so as we know 5^2 is 25, we can do this,

(5^2)^6 so we will multiply the powers to get

5^12 which is your answer :)

pls mark this as brainliestttt

6 0
3 years ago
Y varies directly as x when x= 3 and y =12 find y when x =12
andrew-mc [135]
\bf \qquad \qquad \textit{direct proportional variation}\\\\&#10;\textit{\underline{y} varies directly with \underline{x}}\qquad \qquad  y=kx\impliedby &#10;\begin{array}{llll}&#10;k=constant\ of\\&#10;\qquad  variation&#10;\end{array}\\\\&#10;-------------------------------\\\\&#10;\textit{we know that }&#10;\begin{cases}&#10;x=3\\&#10;y=12&#10;\end{cases}\implies 12=k3\implies \cfrac{12}{3}=k\implies 4=k&#10;\\\\\\&#10;thus\qquad \boxed{y=4x}&#10;\\\\\\&#10;\textit{when x = 12, what is \underline{y}?}\qquad \qquad y=4(12)
3 0
3 years ago
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