A crew can pave 850 feet road in an 8 hour day fine the unit rate
1 answer:
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Answer:
The hotel charge in each city before tax was <u>$5125</u> of the first city and <u>$3625</u> of the second city.
Step-by-step explanation:
Given:
A theater group made appearances into cities the hotel charge before tax and the second city was 1500 higher than the first.
The tax of the first city was 6% and the tax of the second city was 10%.
Total hotel tax paid for two cities with $670.
Now, to find the hotel charge in each city before tax.
Let the hotel charge in first city before tax be
And the hotel charge in second city before tax be
<em>So, as the hotel charge of the second city was 1500 higher than the first.</em>
<em>Thus</em>,
........(1)
<em>And as given, the tax of the first city was 6% and the tax of the second city was 10%, total hotel tax paid for two cities with $670.</em>
6% of + 10% of
= $670.
Substituting the value of from equation (1) we get:
<em>Adding both sides by 150 we get:</em>
<em>Dividing both sides by 0.16 we get:</em>
<em>The hotel charge in first city before tax = $5125.</em>
Now, substituting the value of in equation (1) we get:
<em>The hotel charge in second city before tax = $3625.</em>
Therefore, the hotel charge in each city before tax was $5125 of the first city and $3625 of the second city.
The length of the KN is 4.4
Step-by-step explanation:
We know from Pythagoras theorem
In a right angle ΔLMN
Base² + perpendicular² = hypotenuse ²
From the properties of triangle we also know that altitudes are ⊥ on the sides they fall.
Hence ∠LKM = ∠NKM = 90 °
Given values-
LM=12
LK=10
Let KN be “s”
⇒LN= LK + KN
⇒LN= 10+x eq 1
Coming to the Δ LKM
⇒LK²+MK²= LM²
⇒MK²= 12²-10²
⇒MK²= 44 eq 2
Now in Δ MKN
⇒MK²+ KN²= MN²
⇒44+s²= MN² eq 3
In Δ LMN
⇒LM²+MN²= LN²
Using the values of MN² and LN² from the previous equations
⇒12² + 44+s²= (10+s) ²
⇒144+44+s²= 100+s²+20s
⇒188+s²= 100+s²+20s cancelling the common term “s²”
⇒20s= 188-100
∴ s= 4.4
Hence the value of KN is 4.4
