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3 years ago

What is the absolute value of each number ?

Mathematics

2 answers:

gladu [14]3 years ago

4 0

Answer:

points

Step-by-step explanation:

Alex73 [517]3 years ago

3 0

Answer:

Step-by-step explanation:

Extending my answer to be able to send

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Find the slope of the line that passes through the points (3, 6) and (5, 3).

DanielleElmas [232]

Hello!

To find the slope of the line that passes through the points (3, 6) and (5, 3), we will need to use the slope formula.

Slope formula is $\frac{y_{2}-y_{1} }{x_{2}-x_{1}}$ .

Now, we should assign the given points as x1, y1 or x2, y2. The point (3, 6) can be assigned to x1, y1, and (5, 3) to x2, y2.

Now, substitute the given points into the slope formula.

$\frac{3-6}{5-3} = -\frac{3}{2}$

Therefore, the slope of the line is choice A, -3/2.

7 0

3 years ago

Can i get a OHHHHHH YEAHHHH

Darina [25.2K]

Answer:

AW YEAHHHHHHHHHHHHHHHHHHHHHHHHHHH

Step-by-step explanation:

8 0

3 years ago

Read 2 more answers

The rectangle graphed has a length of 3 and a width of 2. How does the perimeter change if the width is increased by 4? A) The p

storchak [24]

Answer:

The answer to your question is the letter D.

Step-by-step explanation:

Data

First rectangle Second rectangle

length = 3 length = 3

width = 2 width = 2 + 4 = 6

Process

1.- Calculate the Perimeter of the first rectangle

Perimeter = 2l + 2w

Perimeter = 2(3) + 2(2)

= 6 + 4

= 10

2.- Calculate the perimeter of the second rectangle

Perimeter = 2(3) + 2(6)

Perimeter = 6 + 12

Perimeter = 18

3.- Compare both perimeters

Perimeter 1 is smaller than Perimeter 2 by 8 units

4 0

3 years ago

What is the first quartile of the following data set

krok68 [10]

Answer:

The first quartile, Q1, is the median of {3, 5, 7, 8}. Since there is an even number of values, we need the mean of the middle two values to find the first quartile: .

Step-by-step explanation:

Example 1: Find the first and third quartiles of the set {3, 7, 8, 5, 12, 14, 21, 15, 18, 14}

8 0

3 years ago

Consider this scenario: The population of a city increased steadily over a ten-year span. The following ordered pairs show the p

vova2212 [387]

Answer:

Regression function: $y=1986.406+0.0059x$

The function predicts that population will reach 14,000 in year 2068.

Step-by-step explanation:

We have to determine a function $y=b_0+b_1x_1$ by applying linear regression. The data we have is 5 pair of points which relates population to year.

According to the simple regression model (one independent variable), if we minimize the error between the model (the linear function) and the points given, the parameters are:

$b_0=\bar{y}+b_1\bar{x}\\\\b_1=\frac{\sum\limits^5_{i=1} {(x_i-\bar x)(y_i-\bar y)}}{\sum\limits^5_{i=1} {(x_i-\bar x)^2}}$

We start calculating the average of x and y

$\bar x=\frac{2500+2650+3000+3500+4200}{5}=\frac{15850}{5}=3170\\\\ \bar y=\frac{2001+2002+2004+2007+2011}{5}=\frac{10025}{5}=2005$

The sample covariance can be calculated as

$\sum\limits^5_{i=1} {(x_i-\bar x)(y_i-\bar y)}=(2500-3170)(2001-2005)+(2650-3170)(2002-2005)+(3000-3170)(2004-2005)+(3500-3170)(2007-2005)+(4200-3170)(2011-2005)\\\\\sum\limits^5_{i=1} {(x_i-\bar x)(y_i-\bar y)}=2680+1560+170+660+6180\\\\ \sum\limits^5_{i=1} {(x_i-\bar x)(y_i-\bar y)}=11250$

The variance of x can be calculated as

$\sum\limits^5_{i=1} {(x_i-\bar x)^2}=(2500-3170)^2+(2650-3170)^2+(3000-3170)^2+(3500-3170)^2+(4200-3170)^2\\\\\sum\limits^5_{i=1} {(x_i-\bar x)^2}=448900+270400+28900+108900+1060900\\\\\sum\limits^5_{i=1} {(x_i-\bar x)^2}=1918000$

Now we can calculate the parameters of the regression model

$b_1=\frac{\sum\limits^5_{i=1} {(x_i-\bar x)(y_i-\bar y)}}{\sum\limits^5_{i=1} {(x_i-\bar x)^2}}=\frac{11250}{1918000}=0.005865485 \\\\ b_0=\bar{y}+b_1\bar{x}=2005-0.005865485*3170=1986.406413$

The function then become:

$y=1986.406+0.0059x$

With this linear equation we can predict when the population will reach 14,000:

$y=1986.406+0.0059(14,000)=1986.406+82.117=2068.523$

6 0

3 years ago