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3 years ago

Simplify 4(xy^2)^3 x (2x^3y)^2

Mathematics

1 answer:

tangare [24]3 years ago

7 0

4(xy²)³ · (2x³y)²
4(x³y⁶) · 4x⁶y²
4x³y⁶ · 4x⁶y²
16x⁹y⁸

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5 less than the product of -2 and a number is no more than 15.

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-2x - 5 (lesser than or equal to) 15

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Lily likes to collect records. Last year she had 10 records in her collection. Now she has 13 records. What is the percent incre

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3 years ago

In the given diagram, what is the measure of ∠ABC of parallelogram ABCD?

nata0808 [166]

<h3>Answer: C) 136 degrees</h3>

The known acute angle of the triangle is 46 degrees, so the unknown acute angle of that triangle is 90-46 = 44 degrees. In other words, the two acute angles of any right triangle must add to 90, so 46+44 = 90.

The 44 degree angle is adjacent to angle ADC, and it adds to angle ADC to form 180 degrees.

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2 years ago

Read 2 more answers

Which numbers are less than –8/3?<br>–2.6<br>–2.76<br>–2 1/4<br>–11/4<br>–2

e-lub [12.9K]

The number is -11/4 less than -8/3

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2 years ago

the first group of students consists of 10 and their average age was 13 years old the next group consisted of 30 students and th

Kazeer [188]

Answer: The average was 9 years old find the average age of both groups is 10 years old.

Step-by-step explanation:

Formula foe average : $\text{Average} =\dfrac{\text{Sum of all observations}}{\text{Number of observations}}$

Given : The first group of students consists of 10 and their average age was 13 years old.

i.e. $13=\dfrac{\text{Sum of ages of students of first group}}{10}\\\\\Rightarrow\ \text{Sum of ages of students of first group}=13\times10=130$ (1)

The next group consisted of 30 students and their average was 9 years old.

i.e. $9=\dfrac{\text{Sum of ages of students of next group}}{30}\\\\\Rightarrow\ \text{Sum of ages of students of nextgroup}=9\times30=270$ (2)

Then from (1) and (2) , the sum of both groups (first group and next group )students = 130+270 =400

Combined students of both groups (first and next group )= 10+30=40

Now , the average of both groups = $\dfrac{\text{Sum of combined students}}{\text{combined students}}$

$=\dfrac{400}{40}=10$

Hence, the average was 9 years old find the average age of both groups is 10 years old.

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3 years ago