Simplify 4(xy^2)^3 x (2x^3y)^2
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The distance from Humood's house to the school is 500m
<h3>How to determine the distance from Humood's house to the school?</h3>The given parameters are:
Humood's house is (-5,7)
The school is (3,1)
The distance between both points is calculated using
Substitute the known values in the above equation
Evaluate
d = 10
Each unit in the graph is 50m.
So, we have
Distance =10 * 50m
Evaluate the product
Distance = 500m
Hence, the distance from Humood's house to the school is 500m
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