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Butoxors [25]
3 years ago
12

What is the value of x

Mathematics
1 answer:
Alex3 years ago
3 0

Answer:

IDK please add a picture/equation so I can understand ty

Step-by-step explanation:

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Which of the following is the function of FX if F^-1 (x) = ×/8 +3
Anton [14]

Answer:

F(x)=8(x-3)

Step-by-step explanation:

Had to watch a video but I THINK this is the correct answer

8 0
3 years ago
Help please!! 15 points!!
maxonik [38]

Answer:

A and D

Step-by-step explanation:

One side-base right triangle and one angle-based right triangle.

6 0
3 years ago
Read 2 more answers
Can some one help me with the questions?
Katen [24]
Notice that x+4 is one of the denominators, and that x(x+4) is the LCD.
                      x
Thus, mult. ------- by x(x+4), obtaining  x^2.  
                    x+4
Next, mult. [ 1/x + 1/(x+4) by x(x+4), obtaining   x+4 + x = 2x+4 or 2(x+4)
                                                                x^2
Then the simplified fraction becomes  ----------
                                                              2(x+4)

Generally Brainly allows you to post only 1 or 2 questions at a time.  I will do #15 as a courtesy to you, but want you to try #16 yourself (or to post it separately).

-4, 2, 8, 14, ...  is an arithm. seq.  Every new term is equal to the previous term, plus 6:  -4+6 = 2; 2+6=8, and so on.  Thus:  first term is a = -4; common difference is d = 6

a(50) = a(1) + (50-1)(6), or   a(50) = -4 + (49)(6) = 290 (answer)


6 0
4 years ago
Juan has 12 pencils. two-thirds of these pencils are sharpned which model represents the number of sharpend pencils juan has?
Oduvanchick [21]

Answer:

8

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
What is the standard form of the equation of a line for which the length of the normal segment to the origin is 8 and the normal
jeka57 [31]
Slope of line = tan(120) = -tan(60) = - √3
Distance from origin = 8

Let equation be Ax+By+C=0
then -A/B=-√3, or
B=A/√3.
Equation becomes
Ax+(A/√3)y+C=0

Knowing that line is 8 units from origin, apply distance formula
8=abs((Ax+(A/√3)y+C)/sqrt(A^2+(A/√3)^2))
Substitute coordinates of origin (x,y)=(0,0)  =>
8=abs(C/sqrt(A^2+A^2/3))
Let A=1 (or any other arbitrary finite value)
solve for positive solution of C
8=C/√(4/3) => C=8*2/√3 = (16/3)√3

Therefore one solution is
x+(1/√3)+(16/3)√3=0
or equivalently
√3 x + y + 16 = 0

Check:
slope = -1/√3  .....ok
distance from origin
= (√3 * 0 + 0 + 16)/(sqrt(√3)^2+1^2)
=16/2
=8  ok.

Similarly C=-16 will satisfy the given conditions.

Answer  The required equations are
√3 x + y = ± 16 
in standard form.

You can conveniently convert to point-slope form if you wish.




4 0
3 years ago
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