Answer:
50%
Explanation:
Let's assume that the allele "T" gives the normal phenotype while the recessive allele "t" imparts the disease and is lethal in homozygous condition. The genotype of each of the two carrier parents would be "Tt". A cross between Tt and Tt would give the progeny in the following genotype ratio=
Tt x Tt= 1/4 TT: 1/2 Tt: 1/4 tt
Therefore, 1/2 or 50% progeny would be the carrier for the Tay-Sachs disease.
Answer:
yes. Your correct order is 1 Supraspinatus, 2 Subscapularis, 3 Infraspinatus and 4 Teres Major.
Explanation:
<span>The part of the nephron conserves water and minimizes the volume of urine </span>loop of henle.