Answer:
70º
Step-by-step explanation:
i took the test
70°
∠A =112°,
Exterior angle to angle B is 2x, therefore ∠B = 180 -2x (angle on straight line)
Exterior angle to angle C is 2x + 12, therefore ∠C = 180 -(2x +12) (angle on straight line) = 180 - 12 -2x = 168 - 2x
∠A + ∠B + ∠C = 180 (sum o angles in a triangle)
112 + 180 - 2x + 168 - 2x = 180
460 - 4x = 180
4x = 460 - 180 = 280
x = 280/4 = 70
x = 70°
x = -4
–2x + 1 – (–7x + 3) = –4 + 3(x – 2)
-2x + 1 + 7x - 3 = -4 + 3x - 6
-2x + 7x - 3x = -4 - 6 - 1 + 3
2x = -8
x = -8/2
(x - 7) • (5x - 7)
1.028 × 10^8
